# how can call a function

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brahmi ibtissem on 18 Aug 2019
Commented: Walter Roberson on 19 Aug 2019
Hello everyone,
how can i call this function in an other function?
i need to plot a, b, c and d:
function [o, a, b, c, d] = ObjectiveFunction(X )
a=sum(throughputS, 'all');
b=sum(throughputT, 'all');
c=sum(throughputCN, 'all');
d=sum(throughputCR, 'all');
Thanks alot
##### 1 CommentShowHide None
Walter Roberson on 18 Aug 2019
Where are throughputS, throughputT, throughputCN, and throughputCR coming from, and why is the input X not being used? Where is the output o coming from?
Your outputs a, b, c, and d are all going to be scalars, so it is not obvious what you would be plotting?

Walter Roberson on 18 Aug 2019
Example:
N = 100;
o = zeros(N,1); a = zeros(N,1); b = zeros(N,1); c = zeros(N,1); d = zeros(N,1);
for idx = 1 : N
X = rand(15,15);
[o(idx), a(idx), b(idx), c(idx), d(idx)] = ObjectiveFunction(X);
end
plot([a,b,c,d])
legend({'a', 'b', 'c', 'd'});

Luna on 19 Aug 2019
You should define the variables you are going to use as inputs of function. The inputs are written in the paranthesis.
All outputs must be assigned also.
function [o, a, b, c, d] = ObjectiveFunction(throughputS,throughputT,throughputCN,throughputCR)
a=sum(throughputS, 'all');
b=sum(throughputT, 'all');
c=sum(throughputCN, 'all');
d=sum(throughputCR, 'all');
o = 'Luna';
end
Then you call this function as follows in another function:
function hPlot = anotherFunctionToPlotSomeData(w,x,y,z) % you should pass variable reference here.
[o, a, b, c, d] = ObjectiveFunction(w,x,y,z) % where your w,x,y,z becomes throughputS,throughputT,throughputCN,throughputCR respectively inside this function.
% Now you obtained a,b,c,d (I don't know what to do with "o" variable but you get the idea)
figure;
hPlot = plot([a,b,c,d]); % this function also returns the plot handle (line class)
end
##### 1 CommentShowHide None
Walter Roberson on 19 Aug 2019
The a, b, c, d returned are all going to be scalars, so plot([a,b,c,d]) would be a request to plot a line with four points. Although that is well defined, I suspect that is not what the poster had in mind.