## Mean and standard deviation of a field - condition on another field

### SS (view profile)

on 30 Aug 2019
Latest activity Commented on by SS

### SS (view profile)

on 4 Oct 2019 at 11:11

### Matt J (view profile)

Hi. I am working with a structure array S (1 X 50,000) with 10 fields. I want to calculate the mean and standard deviation of field f1 based on a condition on field f2.
For example,
Here is the input,
S(1).f1=[10,20,30 40,50,60] and S(1).f2=[100,20,50,60,70,140];
S(2).f1=[56,98,74,87,99] and S(2).f2=[101,54,69,20,11]
S(3).f1=...... and S(3).f2=.....
S(4).f1=.... and S(4).f2=.....
.
.
S(i).f1=.... and S(i).f2=....
I want to calculate the mean of f1 elements whose corresponding f2 field values are 50 < f2 <=100
Meaning, S(1).f1=[10,40,50] and S(2).f1=[98,74] should be considered in calculation of mean.
I want to calculate several mean values of f1 based on different conditions on f2.

on 31 Aug 2019
Edited by Matt J

### Matt J (view profile)

on 31 Aug 2019

How can I get one single (explicit) mean and standard deviation?
F1=[S.f1];
F2=[S.f2];
F=F1(F2>50 & F2<=100);
MEAN=mean(F);
STD=std(F);

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SS

### SS (view profile)

on 2 Oct 2019 at 7:53
How can I know how many data points/field values are considered in calculation of the mean? Or in other words, how many data points were there based on the above condition?
Matt J

### Matt J (view profile)

on 2 Oct 2019 at 13:58
numel(F)
SS

### SS (view profile)

on 4 Oct 2019 at 11:11
Thanks.

### the cyclist (view profile)

on 30 Aug 2019
Edited by the cyclist

### the cyclist (view profile)

on 30 Aug 2019

The mean and standard deviation of f1, for the elements where 50 < f2 <= 100, can be calculated as follows:
arrayfun(@(x)mean(x.f1(x.f2>50 & x.f2<=100)),S);
arrayfun(@(x) std(x.f1(x.f2>50 & x.f2<=100)),S);
arrayfun will apply a function to each element of a structure array, so it is a vectorized way of doing the operation.

the cyclist

### the cyclist (view profile)

on 30 Aug 2019
I suggest taking a look at the documentation. The first input to arrayfun is the function to apply. So, the use of "x" here is similar to how one would say "f(x) is a function" is mathematics. x is just a placeholder variable, not one of your actual variables. In place of x, MATLAB will use S(1), then S(2), and so on.
You might want to take a look at the documentation for anonymous functions, too.
SS

### SS (view profile)

on 31 Aug 2019
Thanks for the reply. I have tried using the above lines but, unfortunately it creates another structure of size 1 X N in which, some entries are numeric and others are NaN. I have used mean(new created structure) to see whether, it will give one single answer but, it gives NaN as the answer.
How can I get one single (explicit) mean and standard deviation?
the cyclist

### the cyclist (view profile)

on 31 Aug 2019
For a length-L structure, I thought you wanted the L means and standard deviations, one for each element in the structure array. The reason there were some NaNs is presumably that sometime f2 didn't have any elements that fit the condition.
Looks like Matt J got you what you wanted.