Asked by SS
on 30 Aug 2019

Hi. I am working with a structure array S (1 X 50,000) with 10 fields. I want to calculate the mean and standard deviation of field f1 based on a condition on field f2.

For example,

Here is the input,

S(1).f1=[10,20,30 40,50,60] and S(1).f2=[100,20,50,60,70,140];

S(2).f1=[56,98,74,87,99] and S(2).f2=[101,54,69,20,11]

S(3).f1=...... and S(3).f2=.....

S(4).f1=.... and S(4).f2=.....

.

.

S(i).f1=.... and S(i).f2=....

I want to calculate the mean of f1 elements whose corresponding f2 field values are 50 < f2 <=100

Meaning, S(1).f1=[10,40,50] and S(2).f1=[98,74] should be considered in calculation of mean.

I want to calculate several mean values of f1 based on different conditions on f2.

Answer by Matt J
on 31 Aug 2019

Edited by Matt J
on 31 Aug 2019

Accepted Answer

How can I get one single (explicit) mean and standard deviation?

F1=[S.f1];

F2=[S.f2];

F=F1(F2>50 & F2<=100);

MEAN=mean(F);

STD=std(F);

SS
on 2 Oct 2019 at 7:53

Matt J
on 2 Oct 2019 at 13:58

numel(F)

SS
on 4 Oct 2019 at 11:11

Thanks.

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Answer by the cyclist
on 30 Aug 2019

Edited by the cyclist
on 30 Aug 2019

The mean and standard deviation of f1, for the elements where 50 < f2 <= 100, can be calculated as follows:

arrayfun(@(x)mean(x.f1(x.f2>50 & x.f2<=100)),S);

arrayfun(@(x) std(x.f1(x.f2>50 & x.f2<=100)),S);

arrayfun will apply a function to each element of a structure array, so it is a vectorized way of doing the operation.

the cyclist
on 30 Aug 2019

SS
on 31 Aug 2019

Thanks for the reply. I have tried using the above lines but, unfortunately it creates another structure of size 1 X N in which, some entries are numeric and others are NaN. I have used mean(new created structure) to see whether, it will give one single answer but, it gives NaN as the answer.

How can I get one single (explicit) mean and standard deviation?

the cyclist
on 31 Aug 2019

For a length-L structure, I thought you wanted the L means and standard deviations, one for each element in the structure array. The reason there were some NaNs is presumably that sometime f2 didn't have any elements that fit the condition.

Looks like Matt J got you what you wanted.

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