Problem working with popupmenu

Hi guys.

I'm working on GUIDE and i have the next problem:

I have to make a conversor (Decimal, Hexadecimal, octal and bynary)

When i put a number in the edit 1 i have to choose in the "popupmenu1" what value is it (Decimal, Binary, Octal, Hexadecimal) then i choose in the popupmenu2 what value i want convert (Decimal, Binary, Octal, Hexadecimal) and the converted value has to set on the edit2.

mathlab gave me the next message:

"Error in

matlab.graphics.internal.figfile.FigFile/read>@(hObject,eventdata)convertidordecantidades('popupmenu2_Callback',hObject,eventdata,guidata(hObject))

Error while evaluating UIControl Callback."

I hope you guys can help me.

%This is my code%
value = str2double(handles.edittext1.String)
if handles.popupmenu1.Value == 1
    if handles.popupmenu2.Value == 1
        convertedValue = dec2bin(value);
    elseif handles.popupmenu2.Value == 2
    elseif handles.popupmenu2.Value == 3
    elseif handles.popupmenu2.Value == 4
    elseif handles.popupmenu2.Value == 5
    end
elseif handles.popupmenu1.Value == 2
    if handles.popupmenu2.Value == 1
        convertedValue = dec2base(value,8);
    elseif handles.popupmenu2.Value == 2
    elseif handles.popupmenu2.Value == 3
    elseif handles.popupmenu2.Value == 4
    elseif handles.popupmenu2.Value == 5
    end
elseif handles.popupmenu1.Value == 3
    if handles.popupmenu2.Value == 1
        convertedValue = dec2base(value,16);
    elseif handles.popupmenu2.Value == 2
    elseif handles.popupmenu2.Value == 3
    elseif handles.popupmenu2.Value == 4
    elseif handles.popupmenu2.Value == 5
    end
elseif handles.popupmenu1.Value == 3
    if handles.popupmenu2.Value == 1
    elseif handles.popupmenu2.Value == 2
    elseif handles.popupmenu2.Value == 3
    elseif handles.popupmenu2.Value == 4
    elseif handles.popupmenu2.Value == 5
    end
elseif handles.popupmenu1.Value == 5
    if handles.popupmenu2.Value == 1
    elseif handles.popupmenu2.Value == 2
    elseif handles.popupmenu2.Value == 3
    elseif handles.popupmenu2.Value == 4
    elseif handles.popupmenu2.Value == 5
    end
end
handles.edit2.String = sprintf('2.%f',convertedValue)

[Walter Roberson]

value = str2double(handles.edittext1.String)

That line is only valid if the input is decimal, which is not the case when you are converting from any base other than decimal. You should only be using that line when handles.popupmenu1.Value is 4.

[Jhon Rackham]

Hi dear Walter.

What i have to do in this case? Can you help me with that please?

Thanks for the help, master!

[Walter Roberson]

handles.edit2.String = sprintf('2.%f',convertedValue)

That line assumes that convertedValue is internal binary format (which would not be a bad thing) and assumes that the output is decimal, but the output should only be decimal if handles.popupmenu2.Value == 4.

You need to re-read

https://www.mathworks.com/matlabcentral/answers/479628-how-to-make-a-program-that-conver-a-numer-to-binary-decimal-hexadecimal-and-octal#comment_744171

[Jhon Rackham]

I was reading your comments dear Walter, but i still don't know how to do it.

So that means my code is useless or i'am the useless? :(

[Image Analyst]

You're setting the converted value in each one of the if statements, right? Not just 3 of them, right?

[Jhon Rackham]

Yes Image Analyst i'm setting the converted value in each one of the if statements. But i need set the whatever converted value on the edit 2. I don't know if i'm explaining you good.

pd: I'm using your code you gave me days ago, but i'm still having problems. :(

[Image Analyst]

It should work. Post your complete files, both the .fig and .m files. However I'm leaving for the day in a few minutes.

[Walter Roberson]

value_in_str = handles.edittext1.String;
switch handles.popupmenu1.Value
    case 1
        value_in_dec = bin2dec(value_in_str);
    case 2
        value_in_dec = hex2dec(value_in_str);
end
switch handles.popupmenu2.Value
    case 1
        value_out_str = dec2bin(value_in_dec);
    case 2
        value_out_str = dec2hex(value_in_dec);
end
handles.edit2.String = value_out_str;

[Jhon Rackham]

Those are my files, i hope you can help me Image Analyst.

[Image Analyst]

No, you did not have stuff inside each "elseif" block as you claimed. You need to have stuff in each one, like Walter showed. Don't skip any. You can use "if" or switch" - basically the same.

[Jhon Rackham]

O was that, I didn't understood then. Si I only have to do that and how I do the rest? Can you please help me fixing my program? ?

[Jhon Rackham]

God, I don't know why I can't understand. Please, need help.

[Jhon Rackham]

Please Image Analyst, help meeeee. :(

[Walter Roberson]

What happened when you tried the code I posted in

https://www.mathworks.com/matlabcentral/answers/480482-problem-working-with-popupmenu#comment_746191

and what happened when you examined that and then went back to re-read my hints in https://www.mathworks.com/matlabcentral/answers/479628-how-to-make-a-program-that-conver-a-numer-to-binary-decimal-hexadecimal-and-octal#comment_744171 and used my hints to extend your code to handle other bases?

[Jhon Rackham]

It show me errors Mr Roberson.

I notice i'm the useless. Can't do anything. </3

Thats the reazon because i'm asking for favors. :(

[Jhon Rackham]

I don't know if i choose "switch" or "if".

[Jhon Rackham]

Anyways, my program doesn't work.

[Walter Roberson]

It show me errors Mr Roberson.

Would you mind turning your screen by about 7 degrees so that I can read it from here with my binoculars? I'm having terrible difficulty with glare at the moment.

[Jhon Rackham]

Look mr Roberson, the same error.

Can i send you my program for you review it please?

[Jhon Rackham]

I've fixed my problem Mr Roberson.

Please, help me to convert the rest of the values (Octal and Decimal).

I hope you can help me.

[Walter Roberson]

So what did I suggest in https://www.mathworks.com/matlabcentral/answers/479628-how-to-make-a-program-that-conver-a-numer-to-binary-decimal-hexadecimal-and-octal#comment_744171 as the way to handle the other bases ?

[Jhon Rackham]

Mr Roberson, please. don't be bad with me. :(

I was reading your comments, but in the code is not the same is guess, i don't know where i have to put the "sscanf() with '%lo' format" for conver octal number.

When you have time for help me Walter?

[Jhon Rackham]

I know it is not your obligation to help me, but please, you are a teacher here, it would not take you long to help me. Please I beg you.

[Walter Roberson]

>> sscanf('123','%lo')

ans =

  uint64

   83

>> sprintf('%lo', 83)

ans =

    '123'
>> 1*8^2 + 2*8^1 + 3*8^0

ans =

    83

String to be converted goes as the first parameter to sscanf(), method of conversion goes as the second parameter to sscanf()

[Jhon Rackham]

Awesome Mr Roberson.

My program finally work, thanks a lot for the help, GOD bless you.

[Jhon Rackham]

Mr Roberson, are you thereeee?

I forgot to ask you something else.

What can I do to prevent the user from inserting a wrong amount?

For example: if i put this value on the edit1: 123456 and i choose in the popupmenu 1 as binary then i choose on the popupmenu2 i want to convert it as hexadecimal, obvuously it will be an error, because we know 123456 isn't a binary value, maybe for solve this error, we can put a msgbox saying *hey this isn't a binary value*, something like that. But what i have to do for solve this? sorry if i'm bothering you a lot of times.

This is an example:

[Walter Roberson]

Preventing the user from entering a number that is invalid for the currently selected base is complicated. It requires checking every keystroke as the user types it in, and handling deletions yourself, and (for obscure reasons) keeping track of what the user typed in by yourself.

It is a lot easier to validate the number at the time the conversion is requested.

• binary: all characters must be members of the set {'0', '1'}
• octal: all characters must be members of the set {'0', '1', '2', '3', '4', '5', '6', '7'}
• decimal: all characters must be members of the set {'0', '1', '2', '3', '4', '5', '6', '7', '8', '9'}
• hex: all characters must be members of the set {'0', '1', '2', '3', '4', '5', '6', '7', '8', '9', 'A', 'B', 'C', 'D', 'E', 'F', 'a', 'b', 'c', 'd', 'e', 'f'}

https://www.mathworks.com/help/matlab/set-operations.html

[Jhon Rackham]

Oh I see Mr Roberson. Can you give me an example in my code please?

[Walter Roberson]

Consider

ismember('1236', '0':'4')
ismember('1236', ['0':'4', '6':'7'])

[Jhon Rackham]

Thanks Mr Roberson. I have to put it in every case, right?