Plotting circles in a for loop using a time step

Hi there,

I am looking for enlightenment and I am not even sure if this will make sense, but I am trying to plot some cells to help me with reducing costs in a Biology lab. I would like to create a Matlab for loop that plots circles with origin on the circumference of the original plotted circle this will happen at each timestep. This is to mimic cell division.

My original code is:

clear all 
close all
clc
 
for k = 1:5 %numberofruns
    
x0=2;
y0=1;
r=1;
theta=-pi:0.01:pi;
x=r*cos(theta)+x0;
y=r*sin(theta)+y0;
plot(x,y)
hold on
scatter(x0,y0,'or')
% axis square 
% ----------------------------------------
% divide your circle to n sectors
n=2
tet=linspace(-pi,pi,n+1)
xi=r*cos(tet)+x0
yi=r*sin(tet)+y0
 
plot(xi,yi)
 
x0=1;
y0=1;
r=1;
theta=-pi:0.01:pi;
x=r*cos(theta)+x0;
y=r*sin(theta)+y0;
plot(x,y)
hold on
scatter(x0,y0,'or')
% axis square 
% ----------------------------------------
% divide your circle to n sectors
n=2
tet=linspace(-pi,pi,n+1)
xi=r*cos(tet)+x0
yi=r*sin(tet)+y0
 
plot(xi,yi)
 
% for k=1:numel(xi)
% plot([x0 xi(k)],[y0 yi(k)])
% hold on
% end
 
x0=3;
y0=1;
r=1;
theta=-pi:0.01:pi;
x=r*cos(theta)+x0;
y=r*sin(theta)+y0;
plot(x,y)
hold on
scatter(x0,y0,'or')
% axis square 
% ----------------------------------------
% divide your circle to n sectors
n=2
tet=linspace(-pi,pi,n+1)
xi=r*cos(tet)+x0
yi=r*sin(tet)+y0
 
plot(xi,yi)
 
pause(1) %timeinsec
 
shg
end

Thanks in advance!

Answer 1

[the cyclist]

Your code runs fine for me, and creates a figure. What's the problem? What's your question?

I'm going to take a stab at an answer, though. The default axes will mean your mathematical circles will not look like circles. Try

axis equal

to fix that.

[Hannah Haynie]

Hi Cyclist,

Thank you for your answer! My coding here is a work in progress, but that was a helpful suggestion.

Have a nice day.