Plot a scalar as a function of a parameter
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Good morning everybody,
I would like to plot a scalar as a function of a parameter. In particular, I'd like to plot inflation volatility as a function of the parameter (phipi) of monetary policy. Inflation volatility is a vector, so defined:
for n=1:N
for t=2:T
pivolaC(1,n)=(pipiC(t,n)^2)/T;
end
end
PipiC is a function of phipi. Using plot (phipi, pivolaC) just gives me an empty figure.
(By the way, I tried the same trick using a scalar instead of a vector, that is, taking pivolaC(1,1), but the problem persists.
Could somebody help me, please?
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Answers (1)
Bjorn Gustavsson
on 22 Sep 2019
It should be as simple as:
for n = 1:N
for t = 2:T
pipiVal(1,n) = pipiC(t,n); % or however you get the phipi-values correspondin to
pivolaC(1,n) = (pipiC(t,n)^2)/T; % the values for which you calculate pivolaC
end
end
Then the plot should be:
plot(pipiVal,pivolaC)
Further, you only save away the pivolaC-value from the last step in the inner loop. The only reason I can think of in a hurry
where you need to loop anyway is if your pipiC-function stores some state-variable that is updated every time the function
is called. That's a dangerously sensitiv programming pattern, in this case it would be better to have a function that accepts an entire vector of t and loops over them. If you don't do anything like that this should be identical:
for n = 1:N
t = T;
pipiVal(1,n) = pipiC(t,n); % or however you get the phipi-values correspondin to
pivolaC(1,n) = (pipiC(t,n)^2)/T; % the values for which you calculate pivolaC
end
HTH
3 Comments
Bjorn Gustavsson
on 23 Sep 2019
It's not exactly clear what is the problem, to me this:
subplot(2,2,1)
imagesc(zzC)
subplot(2,2,4)
imagesc(pipiC)
subplot(2,2,2)
plot(zzC(:,1),pipiC(:,1),'-',zzC(:,1),pipiC(:,1),'.','markersize',15)
subplot(2,2,3)
plot(zzC(12,:),pipiC(12,:),'-',zzC(12,:),pipiC(12,:),'.','markersize',15)
your zzC matrix as a pseudo-colour image in the top left panel, the pipiC matrix as a pseudo-colour image in the bottom right panel, the first column of zzC and pipiC in the top right panel and the 12th row in the bottom left.
HTH
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