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Using optfun command to solve lagrange multipliers

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Tyler Luzar
Tyler Luzar on 15 Oct 2019
Answered: Koushik Kureti on 12 Mar 2020
hello,
I was given this code to run an optfun command, and I am a little confused how the optfun function works.
function F = optfun(pair)
x = pair(1);
y = pair(2);
F = [3*y+.001*y*exp(x)-4*x, x^2+y^2-25];
end
Any help would be great! I need to solve a lagrange multiplier with this.

Answers (1)

Koushik Kureti
Koushik Kureti on 12 Mar 2020
Hello,
‘optfun’ is function name taking input arguments ‘pair’. Return value of the function is stored in F.
X is assigned with first value of pair. Y is assigned with second value of pair.
Now F has two values, where first value is 3*y+.001*y*exp(x)-4*x and second value are x^2+y^2-25.
At the end F is returned. You can call the function by ‘optfun’ (pair) where defining the pair before calling.
Example:
pair = [1 2];
disp(optfun(pair));
function F = optfun(pair)
x = pair(1);
y = pair(2);
F = [3*y+.001*y*exp(x)-4*x, x^2+y^2-25];
end
Output:
2.0054 -20.0000

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