How to show bin counts' percentage values in Histogram2 tile plot?

Hi Dear Community

I have x and y values*, I want to plot it like a 3D Histogram but on the top view. (It should look like a heatmap with a colorbar).

I made the plot, but I want to show the values percentages or counts on the each rectangle. Here is the code below:

hFig = figure;
hAxes = axes(hFig);

xVals = randn(1,10000);
yVals = randn(1,10000)*5;

xEdges = min(xVals):1:max(xVals);
yEdges = min(yVals):5:max(yVals);

hHist = histogram2(hAxes,xVals,yVals,xEdges,yEdges,'DisplayStyle','tile');
colorbar;

This code only plots the tiled histogram. I looked the hHist object and saw that it has the BinCounts property which actually gives the number of points in each rectangle.

So I calculated percentages as follows:

percentagesMatrix = (hHist.BinCounts / sum(hHist.BinCounts,'all'))*100;

I don't know how to update the rectangles with this percentage values. I want all that matrix is written inside the boxes. And update the colorbar accordingly.

Any help will be appreciated.

Thank you so much! :)

*Note: x and y values normally comes from a tall table as a tall array.

Here is the sample plot below. I want to see numbers inside these squares:

Answer 1

[Luna]

I have solved it writing a function manually add text to each rectangle.

Here is the function:

function hHist = normalized_histogram2(hAxes,xVals,yVals,xEdges,yEdges)
% Creates a 2D Histogram plot of data counts percentage in each bins.
% Add percentage values as text inside each bin. 
% Font size and font weight can be changed manually inside the code or
% added to function inputs. 

% NOTE: If text does not fit the rectangles, change font size or maximize
% figure plot. 

%% inputs: 
% hAxes - axis handle object for the plot
% xVals - a double vector of x values
% yVals - a double vector of y values
% NOTE: xVals and yVals must be the same length
% xEdges - a double vector of x bins
% yEdges - a double vector of y bins

%% outputs:
% hHist - histogram object handle

hist_Counts = histcounts2(xVals,yVals,xEdges,yEdges);
hist_Counts_normalized = (hist_Counts / sum(hist_Counts,'all'))*100;

hHist = histogram2(hAxes,'XBinEdges',xEdges,'YBinEdges',yEdges,'DisplayStyle','tile','BinCounts',hist_Counts_normalized);
colorbar;

xBinCenters = hHist.XBinEdges - [0,diff(hHist.XBinEdges)/2];
yBinCenters = hHist.YBinEdges - [0,diff(hHist.YBinEdges)/2];

for i = 2:numel(xBinCenters)
    
    for j = 2:numel(yBinCenters)
        x_loc = xBinCenters(i);
        y_loc = yBinCenters(j);
        if ~(round(hHist.Values(i-1,j-1),2) == 0)
            text(hAxes,x_loc,y_loc,[num2str(round(hHist.Values(i-1,j-1),2)),'%'],'Color',[0 0 0],'FontSize',10,'FontWeight','bold');
        else
            continue
        end
        
    end
end

Here is the demo:

%% Data Creation:
xVals = randn(1,10000);
yVals = randn(1,1000)*5;
xEdges = min(xVals):1:max(xVals);
yEdges = min(yVals):5:max(yVals);

%% Demo:
hFig = figure;
hAxes = axes(hFig);
normalized_histogram2(hAxes,xVals,yVals,xEdges,yEdges);

% make plot look beautiful:
xlabel('X Data');
ylabel('Y Data');
title('Normalized Histogram 2');
hFig.WindowState = 'maximized';

It will look like below:

Answer 2

[Guillaume]

It's all explained in the doc of histogram2. You don't even have to make the percentage calculation yourself, histogram2 will do it for you if you specify 'Normalization', 'probability':

hHist = histogram2(hAxes,xVals,yVals,xEdges,yEdges,'DisplayStyle','tile', 'Normalization', 'probability');

[Luna]

I know, it normalizes between 0-1 but I want it percent as %. And also I want to see the numbers inside the squares.

[Shashank Bhatia]

Hve you solved it yet?

[Luna]

Yes, I wrote an answer below. You can check it.

[Shashank Bhatia]

Thanks it works for me!!

Best Regards,

SHashank

[Luna]

Your welcome ;)