problem in plotting figure

Dear fellows,i have modified code but i have problem in plotting the last figure(4) and problem is in this line plot(tvec,abs(zifft)).Problem was in my resolution in FFT.Can anyone edit my code please.

clc,close all,clear all
codn=100;
%  fc=6e+3;
fs=36000;
bode=1000;
code=round(rand(1,codn));
code_len=round(1/bode/(1/fs))
 for ii=1:codn   
     x((ii-1)*code_len+1:code_len*ii)=code(ii)
 end
 
 x2 = x-(1/2)    % get rid of most of the dc peak
 
% set up time and frequency arrays 
length(x)
 N = length(x)
delt = 1/fs;
delf = fs/N;
tvec = (1:N)*delt;
 n = 2^nextpow2(N);
fvec = (-n/2:n/2-1)*delf ;   % shifted frequency array
figure(1)
plot(tvec,x2(1,:)+0.5)
title('orignal baseband')
 xlabel('time');
 ylabel('amplitude')
ylim([-1 1.5]);
 y = fftshift(fft(x2,n));   
z=abs(y);
figure(2)
plot(fvec,z)
title('FFT')
xlabel('frequency')
 ylabel('amplitude')
 figure(3)
 z=y;
 z(abs(fvec)>=50& abs(fvec)<=150)=0
 plot(fvec,abs(y))
 xlabel('frequency removed from 50 to 150 HZ');
 ylabel('amplitude')
 figure(4)
zf=fftshift(z)*n;
zifft=ifft(zf)+0.5;
plot(tvec,abs(zifft))
ylim([-1 1.5])
title('recovered signal')
xlabel('time');
 ylabel('amplitude')

Answer 1

[KALYAN ACHARJYA]

In the line no 44, see both variable have different lengths, how can plot two different lengths vectors

here

plot(tvec,abs(zifft))

##

>> whos tvec
  Name      Size              Bytes  Class     Attributes
  tvec      1x3600            28800  double              
>> whos zifft
  Name       Size              Bytes  Class     Attributes

  zifft      1x4096            32768  double     

Do change the code/equations, ensure that, in any plot all vectors must be same length.

Please check with back approach and see length of required variables why vectors reflects those having different lengths.

[imran khan]

sir i know vectors have different lengths but i don't know how to solve this issue can you please help me.

[Daniel M]

You can choose to change your tvec to reflect the usage of n, or you can take the ifft with N as second input.

[imran khan]

i tried but can't figure out

[imran khan]

i am using n dear not N

[Daniel M]

Read what I said again more carefully.

[KALYAN ACHARJYA]

@Imran

Is this?

figure(4)
y=fftshift(fft(x2,length(tvec)));
z=y;
z(abs(fvec)>=50 & abs(fvec)<=150)=0
zf=fftshift(z)*n;
zifft=ifft(zf)+0.5;
plot(tvec,abs(zifft))
%ylim([-1 1.5])
title('recovered signal')
xlabel('time');
ylabel('amplitude')

[imran khan]

no dear its not right.In time domain my signal should be close to figure(1) but with little bit distortion