# How do I remove the brackets from the numeric values around the zeros, so that only the numeric values are left and I am able to use boolean logic to get a solution ( 1 or 0)?

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Michael Tross on 14 Nov 2019
Commented: Michael Tross on 15 Nov 2019
"( (1) | (0) )"
"(0)"
"( (0) | (1) | (0) )"
"( (0) | (0) )"
"( (1) | (0) )"
""
"(0)"
"( (0) & (1) & (0) )"
"(1)"
"( (0) | (0) | (0) )"
""
"(( (0) & (0) & (1) & (0) & (0) & (1) & (0) & (0) ) | ( (0) & (0) & (0) & (1) & (0) & (0) & (1) & (0) & (0) ))"
""
Michael Tross on 15 Nov 2019
Thank you! I was able to get the solutions for the expressions using 'arrayfun' below. If there are anymore "burning" questions, I'll be sure to upload the file.

Daniel M on 14 Nov 2019
Edited: Daniel M on 14 Nov 2019
Hmm, seems like this was an opportunity to apply what you learned yesterday regarding regexprep, if you're trying to remove/replace strings. But you likely don't have to. It also seems that these already are boolean expressions in the form of strings. For example
x = ["( (1) | (0) )", "(0)", "( (0) | (1) | (0) )", "( (0) | (0) )", "( (1) | (0) )", "", "(0)", "( (0) & (1) & (0) )", "(1)", "( (0) | (0) | (0) )", "", "(( (0) & (0) & (1) & (0) & (0) & (1) & (0) & (0) ) | ( (0) & (0) & (0) & (1) & (0) & (0) & (1) & (0) & (0) ))", ""];
boolexp = arrayfun(@str2num, x, 'UniformOutput',0);
ans =
1×13 cell array
Columns 1 through 10
{[1]} {[0]} {[1]} {[0]} {[1]} {0×0 double} {[0]} {[0]} {[1]} {[0]}
Columns 11 through 13
{0×0 double} {[0]} {0×0 double}
Note that it returns empty where the string is empty. You can deal with this with
emptyInds = cellfun(@(v) isempty(v), boolexp, 'UniformOutput',1);
boolexp(emptyInds) = {NaN};
Unfortunately, can't use cell2mat to convert to an array because boolexp contains logicals and NaN. You would have to convert the logicals to doubles first (but then it wouldn't be boolean, would it?). Or deal with the empty cells another way. Or leave it the way it is. Up to you.