How to plot properly a 2d fft of data?

Hi!
Ive generated a wave in a numerical model using a chirp signal and collected the responses of the model in chosen points. How can I plot properly the 2d fft of this data. The responses are in attached mat.
Here is the chirp signal:
t2=0:dt:(2e-4)-dt;
signal2 = chirp(t2,0,9.99900000000000e-05,1e6,'linear');
Is the attached image correct?
thanks in advance

 Accepted Answer

Not entirely. The posted image is the plot of the two-sided Fourier transform after using the fftshift function. The result is that the frequency axis is not correct. (Note that a 2D fft (fft2) is usually applied to images and similarly-constructed matrices. The 1D fft is correct here.)
Try this:
D = load('matlab.mat');
mat = D.mat;
t = 0:numel(mat)-1; % Time Vector (Units: Time Units)
Ts = mean(diff(t)); % Sampling Time Interval
Fs = 1/Ts; % Sampling Frequency
Fn = Fs/2; % Nyquist Frequency
L = numel(t); % Signal Length
FTmat = fft(mat)/L; % Fourier Transform
Fv1 = linspace(0, 1, fix(L/2)+1)*Fn; % Frequency Vector - One-Sided Fourier Transform (Units: Cycles/Time Unit)
Iv = 1:numel(Fv1); % Index Vector
figure
plot(Fv1, abs(FTmat(Iv))*2)
grid
title('One-sided Fourier Transform')
xlabel('Frequency')
ylabel('Amplitude')
Fv2 = linspace(-Fn, +Fn, L); % Frequency Vector - Two-Sided Fourier Transform (Units: Cycles/Time Unit)
figure
plot(Fv2, fftshift(abs(FTmat)))
grid
title('Two-Sided Fourier Transform')
xlabel('Frequency')
ylabel('Amplitude')
producing:
1How to plot properly a 2d fft of data - 2020 01 04.png

6 Comments

Thank you! It's very helpful!
As always, my pleasure!
And could you please describe what does this plot represent in comparison to this data (mat) ?
It is the discrete Fourier transform of ‘mat’, using the time vector (‘t’) that I created for it (substitute the correct time vector for ‘t’ representing the correct sampling times),. and from which I derived frequency vectors ‘Fv1’ and ‘Fv2’.
It is of course the frequency content of ‘mat’, at the discrete frequencies of the respective frequency vectors.
Thank you for such detailed information!
As always, my pleasure!

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