# making dataset 3D data function

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MA Tonima on 9 Jan 2020
Answered: Ridwan Alam on 9 Jan 2020
I have 48 variables with 267000*40 elements. I want to make this into datasets that looks like
1. 267000*40*48
2. 267000*48=> for this one I want to find the mean of the rown and do the same thing as before.
My question is how do I make a function that gives me this without having to do it individually:
this is what I know I should do for each variable
function [data]=datacreate(input)
A=input;
A(isnan(A))=0;
meanA=mean(A,2);
data(:,2)=meanA;
but when I want to do it all at once for all 48 variables, how am I to do this?
function [data]=datacreate(input1,...,input48) %is this notation correct?
for i=1:48 % can this be done without for loop?
A=input; % unsure here, should it be inputi?
A(isnan(A))=0;
meanA=mean(A,2);
data(:,i)=meanA;
i=i+1;
end
data;
Any kind of help is appreciated. Thank you.

Ridwan Alam on 9 Jan 2020
Let's assume your variables are named as 'input01', 'input02', ... 'input48'.
my3Ddata = [];
myMeanData = [];
varnames = whos('input*');
for v = 1:length(varnames)
currInput = eval(varnames(v).name);
currInput(isnan(currInput)) = 0;
my3Ddata = cat(3,my3Ddata,currInput);
currMean = mean(currInput,2);
myMeanData = [myMeanData, currMean];
end
Hope this helps.