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f(x)=sin(x)-x^5=0 providing x is not equals 0 ,function in the interval x [0,3]

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zeki esme
zeki esme on 14 Jan 2020
Answered: Matt J on 14 Jan 2020
f(x)=sin(x)-x^5=0 providing x is not equals 0

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Accepted Answer

Matt J
Matt J on 14 Jan 2020
>> [x0,fval]=fzero(@(x)sin(x)-x.^5,[0.8,1])
x0 =
0.9610
fval =
-1.1102e-16

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