Asked by kavya saxena
on 16 Oct 2012

hi all, i have two vectors one is time and other is amplitude. length of time is 140 whereas length of amplitude is double of it 279, i hv to plot time v/s amplitude but as i use plot(t,y),it gives an error that vectors should be of same length. what should i do....

Answer by Loginatorist
on 16 Oct 2012

Edited by Loginatorist
on 16 Oct 2012

If you know the starting time and ending time for the amplitude, you can just make your own time vector of the correct length.

t = linspace(beginningtime,endingtime,length(y));

plot(t,y)

This assumes the y data was sampled at equal time spacings. If that is not the case, you should give more information about how you ended up with two vectors of different lengths and the relationship between t(idx) and y(idx) for a given idx.

kavya saxena
on 16 Oct 2012

hello,thanx for ur reply. actually my problem is that i hv 2 signals with same time nd i m doing cross correlation using xcorr()function. it makes my signal length double for the same time. i m not getting the cross correlation plot which having one peak value against the time interval. i m sending u what i did

t=startnode(:,1); ux1=startnode(:,2); ux2=endnode(:,2); y=xcorr(ux1,ux2); n=length(t); plot(t,y); it gives error that vector must be same length. when i did according to u it again add the two values of ux1 and ux2 and gives a signal sort of plot, not any peak value as cross correlation function gives. m i using this function correctly? plz help me..

Sign in to comment.

Answer by Jos (10584)
on 24 Feb 2016

You can use interpolation

X_known = [1 2 3 6 8 10] ;

Y_known = [2 5 6 11 18 23] ;

X_desired = 1:10

Y_desired = interp1(X_known, Y_known, X_desired)

plot(X_desired, Y_desired,'rs-', X_known, Y_known,'bo')

Sign in to comment.

Answer by Flavio Baduini
on 3 Apr 2016

Edited by Flavio Baduini
on 3 Apr 2016

The question is of primary importance, I'm facing the same while plotting raw and averaged sensors data.

.

ex:

raw data: y (a vector of length 1000)

averaged data: z (a vector of length 100)

.

You can define a common x-axis and plot your vectors with respect to that. I chose time and I made an average of time values for each 10 samples (10 because I'm averaging 10 values each):

.

time: t (a vector of length 1000)

time averaged: ta (a vector of length 100)

.

Now just plot the values with the same length and you'll get two graphs with the raw and averaged data, in the same plot and with the correct spacing

.

plot(t,y)

plot(ta,z)

Sign in to comment.

Answer by kavya k
on 16 May 2017

Jan
on 16 May 2017

Jan
on 16 May 2017

Sign in to comment.

Answer by SABRINA SABRINA
on 23 Apr 2019 at 15:19

hi

I have a file.txt which has 20 points following x and 17 points following y with combinations E = 20 * 17 points I want to draw E in the xy plane BUT it displays error because they do not have the same dimensions

Sign in to comment.

Opportunities for recent engineering grads.

Apply Today
## 0 Comments

Sign in to comment.