Replace string and then place it again

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Mansour Al Asais
Mansour Al Asais on 9 Mar 2020
Edited: BobH on 18 Mar 2020
Hey, I want to make the output return # as many times as a certain string has, and then, change each # with the corresponding letter in the original string to get a cool ouput.
This is my code so far but I got stuck:
function a = jamstr(strd,time)
for i = 0:1:length(strd)
z = i + 1;
expression = '^.*';
replace = '#';
newStr = regexprep(strd(z),expression,replace)
fprintf(newStr);
pause(time);
a=z;
if z == length(strd)
break
end
end
end
  3 Comments
Ameer Hamza
Ameer Hamza on 18 Mar 2020
Mansour, what is the expected output for
jamstr('Matlab rocks!',0.1)

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Accepted Answer

BobH
BobH on 18 Mar 2020
Edited: BobH on 18 Mar 2020
This is intentionally backwards from what you asked; adjusting it to start with all '#' is for you
function a = jamstr( strd, time )
fprintf( '%s', strd ); % print the entire string
% one backspace for each char
bkspaces = repmat('\b',size(strd));
fmt = [bkspaces '%s']; % format string for fprintf
for i = 1:length(strd)
newStr = strd;
newStr(i) = '#';
fprintf( fmt, newStr );
pause(time);
end
fprintf( fmt, strd ); % restore original
fprintf( '\n' ); % end on a fresh line
end

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