shift horizontal histogram to right

I am trying to shift the entire histogram to right, i.e. at 0.04 instead of 0, without changing the xticks.

6 Comments

Can you show an example output. How do you want to move distogram without moving the xticks.
Personally, I find this graph very confusing. What is the benefit of showing the histogram bars horizontally rather than vertically the way it's normally displayed?
And like Ameer, I certainly don't understand what that would mean for the bars of a histogram count/pdf/cdf/whatever to start at 0.4.
Actually, as you may see below, my final goal is to plot PDF of different set of data in horizontal direction at the same figure.
Do you want to show the pdf as bars or curves? For curves, it can be quite straightforward. For histograms, I couldn't think of a direct way. You will need to add several invisible axes and try to adjust their positions manually. Although possible, only try if it is necessary.
Would the waterfall plot be okay? Check out the waterfall function.
As the figure is 2D, waterfall doesn't work. What I wnt is 2D plot of the horizontal PDF curve for each column vector of dotted data.

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 Accepted Answer

Adam Danz
Adam Danz on 27 Mar 2020
Edited: Adam Danz on 27 Mar 2020
Here's a demo that shows how to compute a probability density estimate for each column of data and how to plot the PDF curve next to each column of data. See inline comments for details.
% Produce a matrix of data where each column of y contains
% data for each vertical stack of dots with x-coordinates
% defined by x.
x = 0:5:50;
y = (randn(50, numel(x)) + linspace(.5,5,numel(x))) .* linspace(.5,2,numel(x));
% Plot the data
plot(x, y, 'bo')
% Compute the probability density estimates (pdfx) for each column of y
nSets = size(y,2);
nPoints = 1000;
points = linspace(min(y(:)), max(y(:)), nPoints);
pdfx = cell2mat(arrayfun(@(col){ksdensity(y(:,col),points)'}, 1:nSets));
% Compute the interval between the x-values
xInterval = mean(diff(x)); % ie, = 5
% Normalize results so that all pdf values are
% between 0 and 85% of the x-interval while maintaining
% the relative heights across all pdf curves.
pdfxNorm = (pdfx - min(pdfx,[],'all')) * (xInterval*.85/range(pdfx(:)));
% NOTE: if you want each pdf curve's height to be independent
% and *not* maintaining the relative hights across all pdf
% curves, use this line instead:
% pdfxNorm = (pdfx - min(pdfx,[],1)) .* (xInterval*.85./range(pdfx,1));
% Horizontally offset the pdfxNorm values so each column
% corresponds to an associated x-value.
pdfxShift = pdfxNorm - min(pdfxNorm,[],1) + x;
% Compute y-values for the pdf curves so that the
% curves do not extend beyond the range of the
% data within each column.
pdfYvals = repmat(points(:),1,size(pdfxShift,2));
pdfYvals(pdfYvals < min(y, [], 1) | pdfYvals > max(y, [], 1)) = NaN;
% Add PDFs to plot
axis tight
xlim([min(x), max(x)+xInterval])
hold on
plot(pdfxShift, pdfYvals, 'r-')
grid on
Here's an example of independent-height option for the pdfxNorm variable, using different random data.

More Answers (0)

Asked:

on 27 Mar 2020

Edited:

on 27 Mar 2020

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