binary sequence input output

I made a random binary sequence x

I want the output to be 5 + N when x =1 and N when x = 0

How can I make this work?

Answer 1

[Walter Roberson]

N+5*x

[Dawon Yoo]

Is there any way to code using if, else?

[Walter Roberson]

Of course there is.

if this_x == 1
    output_location = N + 5;
else
    output_location = N;
end

where this_x one particular entry chosen from x, and where output_location is the place you want to store the result for this particular x entry.

You could also look at:

all_output_locations = all_N_values;

Then examining one x value at a time,

if this_x == 1
    output_location = output_location + 5;
end

where this_x is one particular entry chosen from x, and where output_location refers to the corresponding location inside all_output_locations.

Yes, you are correct, I am deliberately not giving you the complete code, as it is obvious that you are working on homework involving arrays, so you should be reading about array indexing.

Answer 2

[Image Analyst]

Is this homework? If not, here is one way (of many):

x = randi([0, 1], 1, 20) % Create binary sequence of 0's and 1's
N = 3; % Whatever it is....
% Make everything N to start with.
output = N * ones(1, length(x))
% Now need to add 5 to ONLY those indexes in x that have a value of 1.
output(logical(x)) = output(logical(x)) + 5

You get:

x =

0 1 1 0 1 0 0 1 1 1 0 1 0 0 0 0 1 0 1 0

output =

3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3

output =

3 8 8 3 8 3 3 8 8 8 3 8 3 3 3 3 8 3 8 3