find row and column of a value in cell array

I have A matrix of dimension 10*10. C is linear index of non zero element in A

C = {[11],[33;44;54;55],[77;87;98]};

I want to find row and column of linear index in cell array.

result should be

row_col = {[1,2],[3,4; 4,5; 4,6; 5,6],[7,8;7,9;8,10]}

Answer 1

[Ameer Hamza]

C = {[11],[43;54;63;64],[87;97;108]};
A = rand(10);
result = cellfun(@(x) {ind2sub2(size(A), x)}, C);

function y = ind2sub2(sz, ind)
    [r,c] = ind2sub(sz, ind);
    y = [r(:) c(:)];
end

Result:

>> result{1}
ans =
     1     2
>> result{2}
ans =
     3     5
     4     6
     3     7
     4     7
>> result{3}
ans =
     7     9
     7    10
     8    11

Answer 2

[David Hill]

Your example does not get the correct result.

Size_A =[10 10];
row_col = cell([],1);
for i=1:length(C)
    [rows,cols] = ind2sub(Size_A,C{i}(:));
    row_col{i} = [rows,cols];
end