# How can i plot this graph?

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Farooq Hussain on 12 Apr 2020
Commented: Ameer Hamza on 13 Apr 2020
for x=0:0.5:5;
if 0<x<2
y=((1+0.5*(1-cos(2*pi*x/5))).^-0.5);
else x>2;
y=1;
end
end
plot(x,y)
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### Accepted Answer

Ameer Hamza on 12 Apr 2020
Edited: Ameer Hamza on 12 Apr 2020
You can use this vectorized version which is usually faster in MATLAB as compared to for loop.
x = 0:0.1:5;
y = (x<2)*((1+0.5*(1-cos(2*pi*x/5))).^-0.5) + (x>=2)*1;
plot(x,y)
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Ameer Hamza on 13 Apr 2020
You can define it like this
A = @(x) (0<x & x<L).*(1+0.5*(1-cos(2*pi*x/L))-1/2) + (L<x).*1;
f1=@(x,u) u * A(x);

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### More Answers (1)

Edited: Thiago Henrique Gomes Lobato on 12 Apr 2020
Making y=... substitute the whole array. Try something like this:
x=0:0.5:5;
y = zeros(size(x));
for idx = 1:length(x)
if 0<x(idx) && x(idx)<2
y(idx)=((1+0.5*(1-cos(2*pi*x(idx)/5))).^-0.5);
else x(idx)>2;
y(idx)=1;
end
end
plot(x,y)
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