finding the position of the minimum element in the matrix

hello. i need to know the position of the minimum element of the matrix. For example

M= [1 5 7; 2 4 5 ]
M=
1 5 7
2 4 5 

the min is 1 and it's position is (1,1).

How can i find this?

Thanks

Answer 1

[Image Analyst]

You really should use find() rather than min() since find() will find them all and min() only finds the first occurrence, which is important since the min could occur at multiple locations:

M = [1 5 7; 2 4 5; 4, 1, 5]
minValue = min(M(:));
% Find all (row, column) pairs where M = the min value.
[rows, columns] = find(M == minValue)
% Print them out:
for k = 1 : length(rows)
	fprintf('M equals the min value of %f at row = %d, column = %d.\n', ...
		minValue, rows(k), columns(k));
end

You'll see

M =

1 5 7

2 4 5

4 1 5

rows =

1

3

columns =

1

2

M equals the min value of 1.000000 at row = 1, column = 1.

M equals the min value of 1.000000 at row = 3, column = 2.

Answer 2

[madhan ravi]

MIN = min( M(:) );
[ Row, Column ] = ind2sub( size(M), find(MIN == M, 1 ) )

[Umut Oskay]

Can you explain your answer a bit ?

[madhan ravi]

doc find
doc min
doc ind2sub