How to generate permutation of matrix rows in a new matrix?

I have a matrix that will represent a pair of coordinates for each row, so it will be (mx2). For example:

X=[1 2; 3 4; 5 6];

I want to generate a matrix that contains the 6 (3x2x1) possible combinations of these 3 pair of points without repetition. Each 3 rows it would start a new combination until the 6 possible combinations are generated.

Output example:

X1=[3 4; 1 2; 5 6; 
    1 2; 5 6; 3 4;
    5 6; 3 4; 1 2;
    1 2; 3 4; 5 6;
    3 4; 5 6; 1 2;
    5 6; 1 2; 3 4];

Thanks a lot.

[KALYAN ACHARJYA]

More coditional statements required-

X=[1 2; 3 4; 5 6];
data=[repelem(X(:,1),6),repelem(X(:,2),6)];
result=[data(randperm(18),1),data(randperm(18),2)]

Answer 1

[Rik]

This doesn't result in the same order you write, but it gets the job done:

X=[1 2; 3 4; 5 6];
ind=perms(1:size(X,1));
ind=ind';ind=ind(:);
X1=X(ind,:);

X2=[3 4; 1 2; 5 6; 
    1 2; 5 6; 3 4;
    5 6; 3 4; 1 2;
    1 2; 3 4; 5 6;
    3 4; 5 6; 1 2;
    5 6; 1 2; 3 4];

%confirm they are the same:
X1=sortrows(X1);
X2=sortrows(X2);
clc,isequal(X1,X2)

[KALYAN ACHARJYA]

Yes Rik