ODE error message "Error using exist The first input to exist must be a string scalar or character vector"

12 views (last 30 days)
this is my code
syms no(k1,k2,k3,k_1,k_2,k_3,o2,n2,o,h2o,oh,h,t)
n=(k1*o*n2+k_2*no*o+k_3*no*h)/(k_1*no+k2*o2+k3*oh);
eqn1=k1*o*n2-k_1*no*n+k2*n*o2-k_2*no*o+k3*n*oh-k_3*no*h;
fin = diff(no,t)==eqn1;
tspan = [0 10];
i=[0 0];
ra=ode45(fin,tspan,i)
  2 Comments
darova
darova on 29 May 2020
  • you are using symbolic variables. ode45 needs function or function handle
  • your no function depends on several variables (a lot), ode45 works only with one independent variable (ordinary differential equation)
Can you attach original equations?
Abdelrahman Eldaly
Abdelrahman Eldaly on 29 May 2020
Edited: Abdelrahman Eldaly on 29 May 2020
here no function only in t i want no(t). Unable to find explicit solution appears
T=2146;
a=(101.325/(8.314*T))*10^-3;
o2=16.8*a; n2=717*a; o=0.245*a; h2o=171*a; oh=2.75*a; h=0.134*a;
k1=1.8*10^14*exp(-38370/T);
k_1=3.8*10^13*exp(-425/T);
k2=1.8*10^10*T*exp(-4680/T);
k_2=3.8*10^9*T*exp(-28280/T);
k3=7.1*10^13*exp(-450/T);
k_3=1.7*10^14*exp(-24560/T);
syms no(t)
fin = diff(no,t)==k1*o*n2-k_1*no*((k1*o*n2+k_2*no*o+k_3*no*h)/(k_1*no+k2*o2+k3*oh))+k2*((k1*o*n2+k_2*no*o+k_3*no*h)/(k_1*no+k2*o2+k3*oh))*o2-k_2*no*o+k3*((k1*o*n2+k_2*no*o+k_3*no*h)/(k_1*no+k2*o2+k3*oh))*oh-k_3*no*h;
cond= no(0)==0;
no(t)=dsolve(fin,cond)

Sign in to comment.

Answers (2)

darova
darova on 29 May 2020
Try this way: prepare function handle for ode45 solver
fin = @(t,no) k1*o*n2-k_1*no*((k1*o*n2+k_2*no*o+k_3*no*h)/(k_1*no+k2*o2+k3*oh))+k2*((k1*o*n2+k_2*no*o+k_3*no*h)/(k_1*no+k2*o2+k3*oh))*o2-k_2*no*o+k3*((k1*o*n2+k_2*no*o+k_3*no*h)/(k_1*no+k2*o2+k3*oh))*oh-k_3*no*h;
[t,no] = ode45(fin,[0 1e-7],0);
plot(t,no)

Abdelrahman Eldaly
Abdelrahman Eldaly on 29 May 2020
Edited: Abdelrahman Eldaly on 29 May 2020
it should appear like this. where is the error
T=2146;
a=(101.325/(8.314*T))*10^-3;
o2=16.8*a; n2=717*a; o=0.245*a; h2o=171*a; oh=2.75*a; h=0.134*a;
k1=1.8*10^14*exp(-38370/T);
k_1=3.8*10^13*exp(-425/T);
k2=1.8*10^10*T*exp(-4680/T);
k_2=3.8*10^9*T*exp(-28280/T);
k3=7.1*10^13*exp(-450/T);
k_3=1.7*10^14*exp(-24560/T);
fin = @(t,no) k1*o*n2-k_1*no*((k1*o*n2+k_2*no*o+k_3*no*h)/(k_1*no+k2*o2+k3*oh))+k2*((k1*o*n2+k_2*no*o+k_3*no*h)/(k_1*no+k2*o2+k3*oh))*o2-k_2*no*o+k3*((k1*o*n2+k_2*no*o+k_3*no*h)/(k_1*no+k2*o2+k3*oh))*oh-k_3*no*h;
tim=0:0.1:2;
[t,no] = ode45(fin,tim,0);
plot(t,no)
  3 Comments
darova
darova on 29 May 2020
The only idea i have is to separate this long expression into two parts. Because it's hard to check if it's correct or not
% fin = @(t,no) k1*o*n2-k_1*no*((k1*o*n2+k_2*no*o+k_3*no*h)/(k_1*no+k2*o2+k3*oh))+k2*((k1*o*n2+k_2*no*o+k_3*no*h)/(k_1*no+k2*o2+k3*oh))*o2-k_2*no*o+k3*((k1*o*n2+k_2*no*o+k_3*no*h)/(k_1*no+k2*o2+k3*oh))*oh-k_3*no*h;
N = @(no) (...)/(...);
fin = @(t,no) k1*o*n2 - k_1*no*N(no) + ...

Sign in to comment.

Categories

Find more on Symbolic Math Toolbox in Help Center and File Exchange

Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!