How do I plot a X-Y graph in matlab with data using "to workspace" block

I have 2 simulations and I took the data from both simulations and the data I wants is at out.xout{8} and out.yout{8} as a 1x1 double timeseries. How do I plot a X-Y graph out of these data? The code for retrieving data from "to workspace" block is as below:

clear all

close all

clc

%open system

open_system('circlex_ds');

%set parameters for x to workspace

set_param('circlex_ds/To Workspace',...

'VariableName','x')

%output the simulation results

out = sim('circlex_ds');

%plot function

figure()

plot(out.x)

x=out.xout{8};

%open system

open_system('circley_ds');

%set parameters for y to workspaae and for file

set_param('circley_ds/To Workspace',...

'VariableName','y')

%output the simulation results

out = sim('circley_ds');

%plot function

figure()

plot(out.y)

Answer 1

[Ameer Hamza]

Something like this

plot(out.xout{8}.Data, out.yout{8}.Data)

[Geoffrey Lo]

I tried and it has following:

Error using to_workspace_file (line 28)

Brace indexing is not supported for variables of this type.

[Ameer Hamza]

Is out.xout a time series? Maybe try this:

Change line to

out1 = sim('circlex_ds');

and

out2 = sim('circley_ds');

and then try

plot(out1.x.Data, out2.y.Data);

[Geoffrey Lo]

I changed and had following:

Error using plot

Vectors must be the same length.

Error in to_workspace_file (line 28)

plot(out1.x.Data, out2.y.Data,'same')

[Ameer Hamza]

It shows both have a different number of elements. One solution is to use interpolation so that they have the same number of elements

x = out1.x.Data;
y = out2.y.Data;
y_interp = interp1(1:numel(y), y, linspace(1, numel(y), numel(x)));
plot(x, y_interp)

[Geoffrey Lo]

Is there another method, cause the output is suppose to be circle, but instead it turn out to be something like below

[Ameer Hamza]

Can you attach the variables out1 and out2 in a .mat file?

[Geoffrey Lo]

Here are the out1 and out where out 1 is x and out is y

[Ameer Hamza]

There might be some problem with your simulation results. The variable you shared does not appear to be creating a circle. To create a circle, 'x' and 'y' must be sinusoidal signals individually, with a phase shift of 90 degrees. You can see that this is not the case with the data you shared.

[Geoffrey Lo]

It should be a circle as I verified with the matlab code below and plot(out1.x) and plot(out2.y) just give the same results as the code.

[Ameer Hamza]

If you plot out1.x.Data and then plot 'x' in your last script, you will see that they are not the same. Therefore, the Simulink output does not create a circle.

[Geoffrey Lo]

but when I use plot(out.x) and plot(out.y), it is the same as the x and y equation from circle_code_m

[Ameer Hamza]

Oh! I forgot to consider that the time vector might not be equally spaced. Following will work

Time = linspace(0, 7, 1000);
x_interp = interp1(out1.x.Time, out1.x.Data, Time);
y_interp = interp1(out2.y.Time, out2.y.Data, Time);

plot(x_interp, y_interp)

it uses out1 and out2 you shared preiously.

[Geoffrey Lo]

Thanks a lot, it works now :)