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Matlab GUI - Tabgroup visibility - checkbox

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Philipp G.
Philipp G. on 18 Jun 2020
Edited: Adam Danz on 19 Jun 2020
Hi everyone, for a project in university i am creating a gui for an animation and i have a question.
I would like to activate and deactivate a tab group with a checkbox (by default it should be hidden).
During my research in the forum i came across the following:
(from Jorge Paloschi on 5 Jun 2020 at 16:41 -
  • Create a dummy
tg = matlab.ui.container.TabGroup;
  • Suppose your tab is in index 2, then do
app.TabGroup.Children(2).Parent = tg;
  • After this the tab is not visible anymore
  • To make it visible again do the opposite
tg.Children(1).Parent = app.TabGroup;
  • The only remaining action is to permute the children of app.TabGroup so that the last Children goes back to index 2, and voila, visible again in the right order!
You might have to change the property name TabGroup to the one in your application if it is not the default Property name."
But I dont understand how it works and i want to disable all by default. Could anybode help me pls?
  1 Comment
Adam Danz
Adam Danz on 18 Jun 2020
Are you trying to make the entire tab group not visible (which my answer does) or are you trying to control the visibility of each tab?

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Accepted Answer

Adam Danz
Adam Danz on 18 Jun 2020
Edited: Adam Danz on 19 Jun 2020
Control tab selectivity
As of r2020a, there isn't an option to set the visibility or 'enable' property of a tab. However, you can control which tabs can be selected according to a set of checkboxes via the use of a SelectionChangedFcn.
  1. From App designer > Design View, right click the top of the Tab Group (not an individual Tab but the entire group). Go down to 'callbacks' and select "Add SelectionChangedFcn". This will add a function in Code View.
  2. Within the SelectionChangedFcn, determine if the most recently selected tab is associated with a checked or un-checked checkbox. If checked (or unchecked), return the active tab to the previously selected tab. This will prevent the user from selecting tabs associated with checked (or unchecked) check boxes.
This demo restricts tab selection if the checkbox is checked. You can easily do the opposite by changing the conditional statement at the end of the function below.
The SelectionChangedFcn will look like this, below (the entire app is also attached).
% Selection change function: TabGroup
function TabGroupSelectionChanged(app, event)
% Determine which tab was selected
selectedTab = app.TabGroup.SelectedTab;
% Look up the value of the paired checkbox
% Each "case" is the title of a Tab and contains the pair checkbox.
switch selectedTab.Title
case 'Tab'
checkboxValue = app.CheckBox.Value;
case 'Tab2'
checkboxValue = app.CheckBox2.Value;
case 'Tab3'
checkboxValue = app.CheckBox3.Value;
error('Unknown tab: %s.',selectedTab.Title)
% If paired checkbox is checked, return to the previously selected tab
if checkboxValue % --OR-- if ~checkboxValue
app.TabGroup.SelectedTab = event.OldValue;
To toggle the visibility of the entire Tab Group
Here are instructions that sets the visibility of the entire tab group based on a checkbox value.
  1. From within app designer, add the tab group to the app.
  2. Select the added tab group from the top (not the tab but the entire group) and then go to the component browser on the right. Under "Interactivity" you should see a checkbox for "Visible". If you want the default to be off, de-select that.
  3. Add a check box.
  4. Right click the checkbox, go down to "callbacks" and select "Add ValueChangedFcn". That will add a function in code-view.
  5. The selected/de-selected value of the checkbox is stored in app.CheckBox.Value (or whatever your checkbox handle name is). Add the code below within that function. You'll need to substitute the app variables with your correct handle names.
  6. Save the app and test it.
value = app.CheckBox.Value;
if value
app.TabGroup.Visible = 'on';
app.TabGroup.Visible = 'off';
Adam Danz
Adam Danz on 19 Jun 2020
Glad I could help!
Actually, you did the right thing by searching for an answer first. The vast majority of questions asked are not original questions and their answers exist already in the forum or a close-enough answer exists that can be adapted.
It's usually much quicker to search for an answer for 15-20 minutes before putting 10+ minutes into writing a well thought-out question, exchanging commentary for hours or days, and then being fortunate enought to be among the ~50% of questions to actually get an answer, if it even works for your problem, and then spend a day or two understanding it. :D
But in this case, you did ask a very unique and interesting question. I found only 1 other topic in this forum related to this question and it didn't really address the problem. So thanks for the original question!

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