How can I find the column values for a given row?
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Hello. I have a txt file with 1000000 rows and 5 columns and I want to know the values of the 400000 row. Can anyone give me an explicit solution for this? I've tried several ways with the find command.
-5,63200000000000 -35,4210000000000 -3,63965000000000 -37,5098000000000 2,88661461967128
-5,63200000000000 -35,4210000000000 -3,64414000000000 -37,5098000000000 2,88351743875427
-5,63200000000000 -35,4210000000000 -3,64863000000000 -37,5098000000000 2,88042392659483
-5,63200000000000 -35,4210000000000 -3,65312000000000 -37,5098000000000 2,87733409502616
-5,63200000000000 -35,4210000000000 -3,65761000000000 -37,5098000000000 2,87424795591821
-5,63200000000000 -35,4210000000000 -3,66210000000000 -37,5098000000000 2,87116552117777
-5,63200000000000 -35,4210000000000 -3,66659000000000 -37,5098000000000 2,86808680274848
-5,63200000000000 -35,4210000000000 -3,67108000000000 -37,5098000000000 2,86501181261090
-5,63200000000000 -35,4210000000000 -3,67557000000000 -37,5098000000000 2,86194056278253
-5,63200000000000 -35,4210000000000 -3,68006000000000 -37,5098000000000 2,85887306531787
-5,63200000000000 -35,4210000000000 -3,68455000000000 -37,5098000000000 2,85580933230844
-5,63200000000000 -35,4210000000000 -3,68904000000000 -37,5098000000000 2,85274937588285
-5,63200000000000 -35,4210000000000 -3,69353000000000 -37,5098000000000 2,84969320820681
-5,63200000000000 -35,4210000000000 -3,69802000000000 -37,5098000000000 2,84664084148317
-5,63200000000000 -35,4210000000000 -3,70251000000000 -37,5098000000000 2,84359228795198
-5,63200000000000 -35,4210000000000 -3,70700000000000 -37,5098000000000 2,84054755989052
-5,63200000000000 -35,4210000000000 -3,71149000000000 -37,5098000000000 2,83750666961331
-5,63200000000000 -35,4210000000000 -3,71598000000000 -37,5098000000000 2,83446962947215
-5,63200000000000 -35,4210000000000 -3,72047000000000 -37,5098000000000 2,83143645185619
My file is similar to the one I placed above.
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