how to plot the graph for the functions 0<x<2 with y=sin x and y=x^3 and how to get point of intersection?

I will be thankful to your reply..

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Answers (3)

plot(). And fsolve()

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x=linspace(0,2)
y1=cos(x)
y2=x.^2
plot(x,y1)
plot(x,y2)
grid on
i tried these but getting only one line so how will i get intersection point

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x=linspace(0,2,1000);
y1=cos(x);
y2=x.^2;
plot(x,y1);
plot(x,y2);
grid on
I tried this but i need point of intersection of two curves so when i do this in matlab i get only one curve

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I tried your method now i get both the curves but no point of intersection as answer in matlab.
x=linspace(0,2,1000).';
y1=cos(x);
y2=x.^2;
plot([y1 y2]);
MATLAB is not going to tell you what the point of intersection is. You can zoom in near the point of intersection and use the datacursor to find nearby points. Or, without going to that trouble to find a guess, you can use fsolve() to determine where the point of intersection is.
x=linspace(0,2)
y1=cos(x)
y2=x.^2
[x',y1']
[x',y2']
plot(x,y1)
hold on
plot(x,y2)
fsolve(@(x)cos(x)-x.^2,1)
grid on
I used this is this correcet?Does the the graph show point of intersection.
If you want to mark or label the point of intersection on the graph, you will have to record the output of fsolve(), calculate the y corresponding to that x, and then create the form of mark that you want such as by using text() or annotate()
does the output of fsolve means the graph itself?I tried doing it but didnt get it.
x_of_intersection = fsolve(@(x)cos(x)-x.^2,1);
y_of_intersection = cos(x_of_intersection);
text(x_of_intersection, y_of_intersection, 'LOOK HERE')

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Asked:

vb
on 2 Dec 2012

Commented:

on 13 Jan 2024

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