how to assign value to a specific position in cell

A={[10,11,10,7],[7,8,7,6],[11,10,9,9],[7,5,11,5];[9,8,6,11],[10,6,9,7],[6,12,8,9],[7,10,12,9];[10,7,12,6],[8,11,7,5],[8,5,9,9],[10,10,10,10]};
B= [1,1,0,1;0,1,1,1;1,0,1,1;0,1,1,0];
[a,b]=find(~B);
for i=1:numel(a)
    A{a(i),b(i)}=[100 100 100 100];    
 end

Is there any other ways instead of using for loop?

Answer 1

[Walter Roberson]

if size(B,1) > size(A,1)
    A(size(B,1),1) = {};      %extend A if needed
end
if size(B,2) > size(A,2)
    A(1,size(B,2)) = {};      %extend A if needed
end

A(~B) = {[100 100 100 100]};  %replaces the find and the loop

[SM]

Excellent solution. Thank you!

Is there any other ways instead of using for loop for this one?

A={[10,11,10,7],[7,8,7,6],[11,10,9,9],[7,5,11,5];[9,8,6,11],[10,6,9,7],[6,12,8,9],[7,10,12,9];[10,7,12,6],[8,11,7,5],[8,5,9,9],[10,10,10,10]};
C=[1	1	0	1;0	1	1	1;1	0	1	1; 0	1	1	0];
[a,b]=find(~C);
for i=1:numel(a)
    for j=1:size(A,1)
        A{j,a(i)}(b(i))=100;       
    end
end

Thanks in advance!

[Walter Roberson]

You might be able to hide loops behind some cellfun() or arrayfun(), and abusing subsasgn() to do assignments using function call syntax...but otherwise, NO.