How to compare a matrix and make decision on it?

I want to compare the component of a matrix so that if all the component is zero it will give value=0 and if any one component is 1 ,it will give value=1. All the matrix are not of same size always.For example it may be like this:

1×497 logical array

Columns 1 through 21

0 0 0 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0

Columns 22 through 42

0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0

Columns 43 through 63

0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0

Columns 64 through 84

0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0

Columns 85 through 105

0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1

Columns 106 through 126

0 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 1

Columns 127 through 147

0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0

Columns 148 through 168

0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0

Columns 169 through 189

0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0

Columns 190 through 210

0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0

Columns 211 through 231

0 0 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0

Columns 232 through 252

0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0

Columns 253 through 273

0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0

Columns 274 through 294

0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 1 0 0 0 0

Columns 295 through 315

0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0

Columns 316 through 336

0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0

Columns 337 through 357

0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 0 0

Columns 358 through 378

0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0

Columns 379 through 399

0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0

Columns 400 through 420

0 0 0 0 0 1 0 0 0 1 0 0 0 0 0 0 0 0 1 0 0

Columns 421 through 441

0 1 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 0 0

Columns 442 through 462

0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0

Columns 463 through 483

0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0

Columns 484 through 497

0 0 0 0 0 0 0 0 0 0 0 0 0 0

[Jyotirmay Mishra]

I am not sure if get your question right

But something like this can work

let your arrays name be arr;

if(nnz(arr)==0)
    value = 0;
else
    value = 1;
end

[joynob ahmed]

Thank you. It works.

[Walter Roberson]

This does not match the problem statement. The problem statement requires that value = 1 only if any one component of the array is 1, which means that if more than one component is 1 then the result should not be 1.

If "one or more components are 1" is acceptable then

value = any(arr);

[joynob ahmed]

Actually I wanted to find out minimum one nonzero element. If more, there won't be any problem. So I guess it is right for me.

Answer 1

[Walter Roberson]

 n = nnz(YourMatrix) ;
 if n <= 1
   value = n;
  else
   error('more than one entry is 1, result undefined') 
  end