size Inputs must be scalar
5 views (last 30 days)
Show older comments
I want to develop a 3D cubes systematically from 5x5x5 to 15x15x15 with the increments of 1.I developed below code.But there is a problem in the way I am giving the inputs of x,y,z with the increments.
x=5:1:15;
y=5:1:15;
z=5:1:15;
B=zeros(x,y,z);
for i =1:x;
for j=1:y;
for k=1:z;
if ((j==1)|(j==y))&((k==1)|(k==z));
B(i,j,k)=1;
else B(i,j,k)=0;
if((i==1)|(i==x))&((k==1)|(k==z));
B(i,j,k)=1;
else B(i,j,k)=0;
if ((i==1)|(i==x))&((j==1)|(j==y));
B(i,j,k)=1;
else B(i,j,k)=0;
end
end
end
end
end
end
Error
Error using zeros
Size inputs must be scalar.
Error in (line 6)
B=zeros(x,y,z);
0 Comments
Accepted Answer
madhan ravi
on 25 Jul 2020
B = zeros(numel(x), numel(y), numel(z)); % error is gone but I have no idea what’s going on
3 Comments
madhan ravi
on 25 Jul 2020
Edited: madhan ravi
on 25 Jul 2020
for x = x
for y = y
for z = z
zeros(x, y, z)
end
end
end
doc zeros
More Answers (0)
See Also
Categories
Find more on Loops and Conditional Statements in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!