Runga Kutta method 4

I want to solve this equation by Runga kutta method 4.
d2xd/dt2+0.2dx/dt-2.45xd+0.2908xp=
with intial condition
t=to=0
xd=1
xp=0
from t=0 to 100

3 Comments

What have you done so far? What specific problems are you having with your code? Are you allowed to use ode45, or are you required to write your own RK4 code?
Ali
Ali on 20 Aug 2020
This is my code but it does not run.This code is for two equation of similar kind.But if one equation code run that s also ok.
Ali
Ali on 13 Nov 2020
I want to solve second order equation through Ruga kutta method .Please check what is error in this code
m=100;
k=25000;
e=100;
F=15000;
w=(k/m)^0.5;
t(1)=0;
x(1)=0;
v(1)=1;
h=0.1;
tfinal=100;
N=ceil((tfinal-t(1))/h);
f1=@(t,x,v) v;
f2=@(t,x,v) -(k/m)*v-(e/m)*x+(F/m)*cos(w*t);
for j=1:N;
t(j+1)=t(j)+h;
K1x=f1(t(j),x(j),v(j));
K1v=f2(t(j),x(j),v(j));
K2x=f1(t(j)+h/2,x(j)+h/2*K1x,v(j)+h/2*K1v);
K2v=f2(t(j)+h/2,x(j)+h/2*K1x,v(j)+h/2*K1v);
K3x=f1(t(j)+h/2,x(j)+h/2*K2x,v(j)+h/2*K2v);
K3v=f2(t(j)+h/2,x(j)+h/2*K2x,v(j)+h/2*K2v);
K4x=f1(t(j)+h,x(j)+h*K3x,v(j)+h*K3v);
K4v=f2(t(j)+h,x(j)+h*K3x,v(j)+h*K3v);
x(j+1)=x(j)+h/6*(K1x+2*K2x+2*K3x+K4x);
v(j+1)=v(j)+h/6*(K1v+2*K2v+2*K3v+K4v);
end
disp(x(N));
figure;
plot(t,x,'lineWidth',1);
xlabel('t');
ylabel('X','V');
hold on
vel(v(N));
figure;
plot(t,v,lineWidth',1);

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 Accepted Answer

Firstly, you can't have spaces in the name of the m-file. Remove them.
Secondly, remember "length" not "lenght".
Thirdly, pass parameters to the functions in the same order in which you define the functions.
Fourthly, make use of Matlab's error messages!
Here is a working code, but it produces nonsense because of the third point above. Put the parameters in the right order and you might get something sensible.
%input paramters
h=1;
t=1:h:100;
xd=zeros(1,length(t)); %%%%% length not lenght
xp=zeros(1,length(t)); %%%%% length not lenght
vd=zeros(1,length(t)); %%%%% length not lenght
vp=zeros(1,length(t)); %%%%% length not lenght
xdo=1;
vdo=0;
xpo=-1;
vpo=0;
xd(1)=xdo; %%%%% These next four lines must come after the previous four,
vd(1)=vdo; %%%%% and array indices start at 1 not 0 in Matlab.
xp(1)=xpo;
vp(1)=vpo;
%RK4
f1=@(t,xd,xp,vd,vp) vd;
f2=@(t,xd,xp,vd,vp) -0.4198*vd-5.9282*xd-1.5285*xp;
f3=@(t,xd,xp,vd,vp) vp;
f4=@(t,xd,xp,vd,vp) -0.4047*vp+1.5285*xp-7.3774*xd; %%%% xd not xp ?
for i=1:(length(t)-1) %%%%% length not lenght
%%%% The following parameters are not passed to the functions f1, f2,
%%%% etc in the order in which they are defined. You need to correct
%%%% that.
K1xd=f1(t(i),xd(i),vd(i), xp(i),vp(i));
K1vd=f2(t(i),xd(i),vd(i),xp(i),vp(i));
K1xp=f1(t(i),xp(i),vp(i), xd(i),vd(i));
K1vp=f2(t(i),xp(i),vp(i),xd(i),vd(i));
K2xd=f1(t(i)+h/2,xd(i)+h*K1xd/2,vd(i)+h*K1vd/2,xp(i)+h*K1xp/2,vp(i)+h*K1vp/2);
K2vd=f2(t(i)+h/2,xd(i)+h*K1xd/2,vd(i)+h*K1vd/2,xp(i)+h*K1xp/2,vp(i)+h*K1vp/2); %%%%%%%%%
K2xp=f1(t(i)+h/2,xp(i)+h*K1xp/2,vp(i)+h*K1vp/2,xd(i)+h*K1xd/2,vd(i)+h*K1vd/2);
K2vp=f2(t(i)+h/2,xp(i)+h*K1xp/2,vp(i)+h*K1vp/2,xd(i)+h*K1xp/2,vd(i)+h*K1vd/2); %%%%%%%%%
K3xd=f1(t(i)+h/2,xd(i)+h*K2xd/2,vd(i)+h*K2vd/2,xp(i)+h*K2xp/2,vp(i)+h*K2vp/2);
K3vd=f2(t(i)+h/2,xd(i)+h*K2xd/2,vd(i)+h*K2vd/2,xp(i)+h*K2xp/2,vp(i)+h*K2vp/2);
K3xp=f1(t(i)+h/2,xp(i)+h*K2xp/2,vp(i)+h*K2vp/2,xd(i)+h*K2xd/2,vd(i)+h*K2vd/2);
K3vp=f2(t(i)+h/2,xp(i)+h*K2xp/2,vp(i)+h*K2vp/2,xd(i)+h*K2xd/2,vd(i)+h*K2vd/2);
K4xd=f1(t(i)+h,xd(i)+h*K3xd,vd(i)+h*K3vd,xp(i)+h*K3xp,vp(i)+h*K3vp);
K4vd=f2(t(i)+h,xd(i)+h*K3xd,vd(i)+h*K3vd,xp(i)+h*K3xp,vp(i)+h*K3vp);
K4xp=f1(t(i)+h,xp(i)+h*K3xp,vp(i)+h*K3vp,xd(i)+h*K3xd,vd(i)+h*K3vd);
K4vp=f2(t(i)+h,xp(i)+h*K3xp,vp(i)+h*K3vp,xd(i)+h*K3xd,vd(i)+h*K3vd); %%%%%%% K4vp not K4vd
xd(i+1)=xd(i)+h/6*(K1xd+K1xp+2*K2xd+2*K2xp+2*K3xd+2*K3xp+K4xd+K4xp);
vd(i+1)=vd(i)+h/6*(K1vd+K1vp+2*K2vd+2*K2vp+2*K3vd+2*K3vp+K4vd+K4vp);
xp(i+1)=xp(i)+h/6*(K1xp+K1xd+2*K2xp+2*K2xd+2*K3xp+2*K3xd+K4xp+K4xd);
vp(i+1)=vp(i)+h/6*(K1vp+K1vd+2*K2vp+2*K2vd+2*K3vp+2*K3vd+K4vp+K4vd);
end
%plots
plot(t,xd)
hold on
plot(t,xp)

6 Comments

Ali
Ali on 20 Aug 2020
Thanks
Ali
Ali on 13 Nov 2020
I want to solve second order equation through Ruga kutta method .Please check what is error in this code
m=100;
k=25000;
e=100;
F=15000;
w=(k/m)^0.5;
t(1)=0;
x(1)=0;
v(1)=1;
h=0.1;
tfinal=100;
N=ceil((tfinal-t(1))/h);
f1=@(t,x,v) v;
f2=@(t,x,v) -(k/m)*v-(e/m)*x+(F/m)*cos(w*t);
for j=1:N;
t(j+1)=t(j)+h;
K1x=f1(t(j),x(j),v(j));
K1v=f2(t(j),x(j),v(j));
K2x=f1(t(j)+h/2,x(j)+h/2*K1x,v(j)+h/2*K1v);
K2v=f2(t(j)+h/2,x(j)+h/2*K1x,v(j)+h/2*K1v);
K3x=f1(t(j)+h/2,x(j)+h/2*K2x,v(j)+h/2*K2v);
K3v=f2(t(j)+h/2,x(j)+h/2*K2x,v(j)+h/2*K2v);
K4x=f1(t(j)+h,x(j)+h*K3x,v(j)+h*K3v);
K4v=f2(t(j)+h,x(j)+h*K3x,v(j)+h*K3v);
x(j+1)=x(j)+h/6*(K1x+2*K2x+2*K3x+K4x);
v(j+1)=v(j)+h/6*(K1v+2*K2v+2*K3v+K4v);
end
disp(x(N));
figure;
plot(t,x,'lineWidth',1);
xlabel('t');
ylabel('X','V');
hold on
vel(v(N));
figure;
plot(t,v,lineWidth',1);
Try the following
m=100;
k=25000;
e=100;
F=15000;
w=(k/m)^0.5;
t(1)=0;
x(1)=0;
v(1)=1;
h=0.01; %%%% Original timetep was too large
tfinal=1; %%%% Not much point in going as far as 100.
N=ceil((tfinal-t(1))/h);
f1=@(t,x,v) v;
f2=@(t,x,v) -(k/m)*v-(e/m)*x+(F/m)*cos(w*t);
for j=1:N
t(j+1)=t(j)+h;
K1x=f1(t(j),x(j),v(j));
K1v=f2(t(j),x(j),v(j));
K2x=f1(t(j)+h/2,x(j)+h/2*K1x,v(j)+h/2*K1v);
K2v=f2(t(j)+h/2,x(j)+h/2*K1x,v(j)+h/2*K1v);
K3x=f1(t(j)+h/2,x(j)+h/2*K2x,v(j)+h/2*K2v);
K3v=f2(t(j)+h/2,x(j)+h/2*K2x,v(j)+h/2*K2v);
K4x=f1(t(j)+h,x(j)+h*K3x,v(j)+h*K3v);
K4v=f2(t(j)+h,x(j)+h*K3x,v(j)+h*K3v);
x(j+1)=x(j)+h/6*(K1x+2*K2x+2*K3x+K4x);
v(j+1)=v(j)+h/6*(K1v+2*K2v+2*K3v+K4v);
end
disp(x(N));
figure;
plot(t,x);
xlabel('t');
ylabel('X, V');
hold on
disp(v(N));
figure;
plot(t,v);
Ali
Ali on 13 Nov 2020
Thank
what changes are made if I increase time upto to 100 sec.
Try it. It works, it's just a boring result!
Ali
Ali on 13 Nov 2020
Thanks Alan

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Asked:

Ali
on 20 Aug 2020

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Ali
on 13 Nov 2020

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