Efficient way/best practice to slice array under a logical condition as well as other conditions

I did not know how to properly title this question, so please bear with me.
Simply put, with the following two arrays:
A = [0 1 0 1 0 0 0 1]'
B = [800 1 1 60;
900 3 0 30;
900 4 0 30;
900 6 0 30;
900 7 0 30;
900 11 0 30;
900 1 2 60;
1000 1 2 60;
]
Note that A and B have the same number of columns.
I would like, for example, to slice B under the following constraints:
  • A == 1
  • B(:,3) ~= 0
  • Keep only columns [2 3 4] of B
This is the way I am doing it at the moment:
B_sliced = B(A==1 & B(:,3)~=0,[2 3 4]);
Alternatively, one could do:
B_sliced = B(logical(A) & B(:,3)~=0,[2 3 4]);
With tic toc and large matrices, I am not noticing much of a difference in performance.
Is there a best practice regarding combining logical with non-logical conditions? Should I keep something in mind, or it doesn't really matter which way I go? Is there a way to make any of these more efficient by using "find"?
I hope you can enlighten me a bit! Thanks.

1 Comment

Don't split the hair, it doesn't really matter.
Just do the way te code looks most readable to you.

Sign in to comment.

Categories

Find more on Programming in Help Center and File Exchange

Products

Release

R2018b

Asked:

on 4 Oct 2020

Answered:

on 4 Oct 2020

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!