Formula for finding point on a line given distance along a line.

Start point - (x0, y0)

End point - (x1, y1)

x = x0 +- c/sqrt(1+m^2)

This equation is not working for my case because I only need the middle point between the two, not the one away from the end point.

I want to find the point (xt,yt).

Can anyone guide me this?

I am asking this for the path finder (rapidly exploring random trees) method.

[Ameer Hamza]

Can you explain more? What are c and m? Drawing an image and marking the points you want to find will be helpful.

[Wai Han]

@Ammer Hamza, I've got this problem. Please help me with this Question.

Answer 1

[KSSV]

P0 = rand(1,2) ; 
P1 = rand(1,2) ; 

% Normalize the line 
v = P1-P0 ; 
vunit = v/norm(v) ; 
% Get a point from P0 at a distance t 
t = 0.5 ; 
Pt = P0+t*vunit ; 
% Check, find the diatnce btween Pt and P0
d = sqrt(sum((Pt-P0).^2)) ;

% plot 
plot([P0(1) P1(1)],[P0(2) P1(2)],'r')
hold on
plot(Pt(1),Pt(2),'*k')

[Wai Han]

Thank you so much! It helps me a lot.