Normalizing histfit plots to all have the same height of 1

Hello,

I have below my code that successfully just plots the fits without the histograms, thanks to another answered question on here. As you can see I am plotting multiple fits onto the same figure, but I want them all to have the same height of ,1 but can't seem to find a direct way to do that from here. Please let me know if you have a solution! I can imagine it isn't that difficult, but I am still learning MATLAB. Thank you!

figure(1)
h70 = histfit(x70, 10000);
set(h70(2), 'color', 'm')
delete(h70(1))
hold on

h90 = histfit(x90, 10000);
set(h90(2), 'color', 'y')
delete(h90(1))
hold on
.
.
.

[Brett Ruben]

I have also tried an answer by Star Strider, here is the code and here is the figure it generates. Looks like the Y-axis certainly has changed, but the plots are not peaking at 1.

figure(1)
h70 = histfit(x70, 10000);
set(h70(2), 'color', 'm')
delete(h70(1))
yt70 = get(gca, 'YTick');
set(gca, 'YTick', yt70, 'YTickLabel', yt70/numel(x70))
hold on

h90 = histfit(x90, 10000);
set(h90(2), 'color', 'y')
delete(h90(1))
yt90 = get(gca, 'YTick');
set(gca, 'YTick', yt90, 'YTickLabel', yt90/numel(x90))
hold on
.
.
.

Answer 1

[Star Strider]

In a Comment in Getting FWHM from distribution fitter you requested my attention to this.

Try this:

a = randn(1,1E+4);                                      % Create Data
b = randn(1,1E+4)*2;                                    % Create Data

figure
ha = histfit(a,1000);
set(ha(2), 'color','m')
yd = ha(2).YData;
ha(2).YData = ha(2).YData/max(ha(2).YData);
delete(ha(1))
hold on
hb = histfit(b,1000);
set(hb(2), 'color','y')
hb(2).YData = hb(2).YData/max(hb(2).YData);
delete(hb(1))
hold off

.

[Brett Ruben]

You are the best! Thank you very much! Here is a picture of what it has done.

[Star Strider]

I very much appreciate your compliment!

As always, my pleasure!

[Matthew ODonohue]

Star Strider,

Awesome solution. Thank you so much, seriously. However, what was your motive for defining the variable "yd"? And what is it?

Thank you.