one script two anonymous functions

I do not undestand when I wrong in my code

thank you so much for yor help

ThirdSide = @(a,b,C) sqrt(a^2+b^2-(2*a*b*cos(C)));
TriangleArea = @(a,b,C) ((a*b)/2)*sin(C);

SideC =ThirdSide(5,8,50*pi/180)
AreaABC=TriangleArea(5,8,50*pi/180)

Answer 1

[Steven Lord]

Based on the problem description I'm guessing C is an angle in degrees, not radians. If that's the case take a look at the sind function.

Answer 2

[Fanele]

ThirdSide=@(a,b,C) sqrt(a^2+b^2-2*a*b*cos(C*pi/180))

ThirdSide = function_handle with value:
    @(a,b,C)sqrt(a^2+b^2-2*a*b*cos(C*pi/180))

TriangleArea=@(a,b,C) (((a*b)/2)*sin(C*pi/180))

TriangleArea = function_handle with value:
    @(a,b,C)(((a*b)/2)*sin(C*pi/180))

SideC=ThirdSide(5,8,50)

SideC = 6.1300

AreaABC=TriangleArea(5,8,50)

AreaABC = 15.3209