how to count the number of a specific value in a cell array and how to access the index of each value

Dear all,

i am now working with a cell array with fixed length:

VtStatus = {1,0,0,0,0,0};

and I also created 6 checkboxes to manage this cell array, e.g.: If I want to mark the checkboxes instead of the 3rd and the 5th, then this array goes like this:

VtStatus = {1,1,0,1,0,1};

Here comes the question: I want to know how many ''1'' are in this array and also the position of these ''1'' (e.g: I want to get the index of ''active checkboxes'' as a string '1-2-4-6' ). Which functions should I use?

Many thx!

Answer 1

[Ameer Hamza]

If possible, use numeric array for this type of data. They will be much more efficient and easy to deal with. For cell array, you can try something like this

VtStatus = {1,1,0,1,0,1};
loccation = find([VtStatus{:}]);
num = numel(loccation);
active_checkboxes = strjoin(string(loccation), '-');

Result

>> loccation
loccation =
     1     2     4     6
>> num
num =
     4
>> active_checkboxes
active_checkboxes = 
    "1-2-4-6"

Answer 2

[João Mendes]

To know the positions of the active checkboxes you can write:

active= find([a{:}]==1)

To know how many are active, i.e., how many '1's' exist, youc an write:

number=size(active,2)

It helps?

Answer 3

[Superficial]

Convert from a cell to a vector and it's easy.

VtStatus = {1,1,0,1,0,1};

vec=[VtStatus{:}]  % Convert to a vector

inds=find(vec==1)  % The index of each cell equal to one
str=num2str(inds)      % You can convert inds to a string if you like

count = length(inds)  % The number of cells equal to one

Gives the answers:

vec =
     1     1     0     1     0     1

inds =
     1     2     4     6

str =
    '1  2  4  6'

count =
     4