How to plot the function x(t) = 10e^(3t)*u(t) thanks a lot

I have this question and I am not good with coding using matlab. Can someone please help me

[Carlos]

The problem here is that you are no specifying the time interval in which you want to plot the function, and you are not specifying what u(t) is.

Imagine you want to plot the function x(t) = 10e^(3t) in the time interval t=[0,2], sampling with time interval t=0.1, then the code is:

>> t=0:0.1:2;
>> y=10*exp(3*t);
>> plot(t,y)

Answer 1

[zohaib ahmed malik]

t=0:0.1:2;

>> y=10*exp(3*t);

>> plot(t,y)

[Muganza Yumba]

u(t) is a unit step signal, which has a value of 0 for negative time and has a value of 1 for positive time, and can be plotted by calling heaviside(t),

t=0:0.1:2;

>> y=10*exp(3*t).*heaviside(t);

>> plot(t,y)

Answer 2

[Revanth]

t=-5:0.1:5;
if(t>=0)
    u=1;
end
if(t<0)
    u=0;
end
x=10*exp(3*t).*u;

Unrecognized function or variable 'u'.

plot(t,x);
xlabel('t'); ylabel('x(t)');
title('signal x(t)');

[Sam Chak]

Hi @Revanth, The code you provided has an error. In MATLAB, a vector cannot be used as the condition in an if statement. Consider revising your code and keep the if statement. 😃

t       = -5:0.1:5;
u       = zeros(size(t));   % Pre-allocation
u(t>=0) = 1;
x       = 10*exp(3*t).*u;

plot(t, x);, grid on
xlabel('t');
ylabel('x(t)');
title('signal x(t)');