How can I use uigetfile to get the file path?
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Hello, I was wondering if I could use the function uigetfile to get the complete file path string.
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Accepted Answer
Image Analyst
on 12 Apr 2013
The documentation for uigetfile() is remiss in not showing any examples that use fullfile() to construct the full file name of the chosen file. Here is how you do it:
[baseName, folder] = uigetfile();
fullFileName = fullfile(folder, baseName)
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