How can I use uigetfile to get the file path?

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Hello, I was wondering if I could use the function uigetfile to get the complete file path string.

Accepted Answer

Image Analyst
Image Analyst on 12 Apr 2013
The documentation for uigetfile() is remiss in not showing any examples that use fullfile() to construct the full file name of the chosen file. Here is how you do it:
[baseName, folder] = uigetfile();
fullFileName = fullfile(folder, baseName)
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Alejandro
Alejandro on 12 Apr 2013
Thank you! I was looking for the full file path and this is it!

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More Answers (1)

Matt J
Matt J on 12 Apr 2013
The 2nd output argument of uigetfile() gives the path info. See
>>doc uigetfile
  1 Comment
Jan
Jan on 12 Apr 2013
Exactly. Reading the help and doc text is a good strategy, when you have questions conderning a command.

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