solve non linear equations
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i wrote the code for non linear equations. But i got the error .can u please tell me how to rectify this error
lear all
close all
syms S J
Qo=26560 %%m3/day
R=0.56
So=220
V=2434.67 %%
X=3000
Ks=0.27
k=1.076
Y=0.39
kd=0.04
bs=0.15
Xf=0.49
Df=1.04
Dw=1.3
L=0.04
a=2.24
bt=kd+bs
Smin=Ks/((Y*k/bt)-1)
Lstar=L*(sqrt(k*Xf/Ks*Df))*Df*Dw
Sstar=S/Ks
jstar=(J/sqrt(Ks*k*Xf*Df))
Sstar_min=(1/(Y*k*(bt-1)))
r=(So-S)/So
eqn1=Qo*(1+R)*(1-r)*(So-S)-a*V*J==0;
eqn2=sqrt((Lstar^1.76)+5.2*(Sstar-Sstar_min)-(Lstar^0.88))/2.6==jstar^0.88;
Answers (2)
Alan Stevens
on 15 Jan 2021
Add these lines at the end to get the values of S and J
Soln = vpasolve([eqn1, eqn2],[S, J],[1 1]);
disp(Soln.S)
disp(Soln.J)
4 Comments
sunitha
on 16 Jan 2021
Alan Stevens
on 16 Jan 2021
The [1 1] is simply a starting guess for the variables. i.e the initial guess for S is 1 and that for J is 1.
sunitha
on 16 Jan 2021
Alan Stevens
on 16 Jan 2021
Well, the following gets results and writes to an Excel spreadsheet
syms N
Qo=26560;
R=0.56;
No=xlsread('suspended','Sheet1','C2:C5');
X=xlsread('suspended','Sheet1','F2:F5');
r=(No-N)/No;
V=2435;
k=1.076;
Kn=0.27;
nX=size(X,1);
solutions=cell(nX,1);
Nres = zeros(3,nX);
for S=1:nX
solutions{S}=solve(Qo.*(1+R).*(No(S)-N)*r(S)-V*((X(S)*k*N)/(Kn+N)),N);
Nres(:,S) = vpa(solutions{S});
end
fname = 'suspendedresults.xlsx';
xlswrite(fname,Nres)
However, I've no idea what your code is all about, so can't comment on the validity of the result.
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