Find ascii numbers from cells

I would like to find ascii numbers from cells. My file has words/letters (cell arrays). I would like to calculate ascii number for each cell.
Could you help me please?

 Accepted Answer

Matlab stores characters as Unicode characters which incorporates the ASCII character set as the first 128 sumbols.
Convert characters -->Unicode/ASCII using double('__')
Convert Unicode/ASCII-->characters using char(__)
double('a')
ans = 97
double('Matlab')
ans = 1×6
77 97 116 108 97 98
char([77 97 116 108 97 98])
ans = 'Matlab'
double('😎') % Not ASCII
ans = 1×2
55357 56846
To apply that to a cell array,
z = {'Here','is an','example','!',''};
a = cellfun(@double, z, 'UniformOutput', false)
a = 1x5 cell array
{1×4 double} {1×5 double} {1×7 double} {[33]} {0×0 double}
a{1} % "Here"
ans = 1×4
72 101 114 101
a{2} % "is an"
ans = 1×5
105 115 32 97 110
--or--
v = cell2mat(cellfun(@double, z, 'UniformOutput', false))
v = 1×17
72 101 114 101 105 115 32 97 110 101 120 97 109 112 108 101 33
Put the cell array of ASCII codes back into char vector
c = strjoin(cellfun(@char, a, 'UniformOutput', false))
c = 'Here is an example ! '

3 Comments

Excuse me, I did not mentioned that I have a file, (I am upoloading it), I have tried cell2table, table2array, and after that double and din not work. Can you understande what I am doing wrong?
How are you reading in the file
C = readcell('names.xlsx');
a = cellfun(@double, C, 'UniformOutput', false)
% a =
% 7×1 cell array
% {1×4 double}
% {1×6 double}
% {1×6 double}
% {1×4 double}
% {1×4 double}
% {1×3 double}
% {1×7 double}
Thank you. I have one more question. I would like to use crosscorr funtion, in order to correlate each cell (to correlate cell 1st column with the cell in second column etc).
my code is
Pin = readcell('names_2.xlsx');
A = cellfun(@double, Pin, 'UniformOutput', false);
a=A(2:end,1);
b=A(2:end,2);
[c,lag]=crosscorr(a,b)
But command window shows me :
The value of 'y1' is invalid. Expected first input series to be one of these types:
double
Instead its type was cell.
Could you help me please?

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on 23 Jan 2021

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on 24 Jan 2021

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