How do I remove an element from cell based on the size of the array within the cell

For this code, I took a row vector of doubles and separated it into a cell array based on values that are within 5 of the previous number in the array. Now what I want to do is remove any cells that only have one value in it. I have been able to transform the 1 x 1 array to a 0 x 0, but I haven't been able to remove the cell entirely.

What I did to remove the array:

for i = 1:length(ClusterCell)
    if size(ClusterCell{1,i}) == [1 1]
        ClusterCell{1,i} = [];
    end
end

when I try ClusterCell(1, i) = [ ]; I get the error "A null assignment can have only one non-colon index."

How do I completely remove cell containing the 1 x 1 array instead of deleting to contents within?

Thank you for you Help!

Answer 1

[David Hill]

for i = 1:length(ClusterCell)
    if size(ClusterCell{i}) == [1 1]
        ClusterCell(i) = [];
    end
end

Answer 2

[Adam Danz]

You can use cellfun with numel to eliminate cells with only 1 element.

Assuming ClusterCell is a cell array,

ClusterCell(cellfun(@numel, ClusterCell)==1) = [];

If you want to remove the empty, 0x0 cells along with the 1x1 cells,

ClusterCell(cellfun(@numel, ClusterCell)<=1) = [];