Plotting Timetable in Matlab
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load_demand=readtable("Demand_timeseries_1hourResolution.xlsx");
TR=table2timetable(load_demand);
Time=TR({'05-05-2020','05-06-2020 00:00:00'},:);
T = timetable2table(Time)
x=T{2:end,1}
y=T{2:end,3}
plot(x,y)
I am trying to plot my timetable, but it will only plot a single point for it. So instead of plotting the whole data series for 'Time' it only plots for the first point. I tried converting it to an array but that didn't work out too well. Hopefully somebody can help me
Accepted Answer
More Answers (2)
Duncan Po
on 19 Feb 2021
0 votes
The line:
Time=TR({'05-05-2020','05-06-2020 00:00:00'},:);
only extracts two rows from TR. So Time only has two rows. Then when you define x and y, the first row is discarded, so x and y are scalar. That's the reason only one point is plotted.
If you want the entire series, just use the entire TR instead of extracting only two rows.
17 Comments
Anders Vigen
on 20 Feb 2021
Walter Roberson
on 20 Feb 2021
https://www.mathworks.com/help/matlab/ref/timerange.html#d122e1343230
Anders Vigen
on 20 Feb 2021
Walter Roberson
on 20 Feb 2021
load_demand = readtable("Demand_timeseries_1hourResolution.xlsx");
TR = table2timetable(load_demand);
subset = timerange(datetime('05-05-2020', 'InputFormat', 'MM-dd-yyyy'),datetime('05-06-2020 00:00:00', 'InputFormat', 'MM-dd-yyyy HH:mm:ss'));
Time = TR(subset,:);
T = timetable2table(Time)
x=T{2:end,1}
y=T{2:end,3}
plot(x,y)
By the way, why are you skipping the first row?
Note: using timerange would be a lot easier if you were using a standard way of representing the dates.
subset = timerange('2020-05-05', '2020-05-06')
The mess with calling datetime() with 'InputFormat' is only needed because month-day-year is not one of the recognized international time formats.
Anders Vigen
on 20 Feb 2021
Edited: Anders Vigen
on 20 Feb 2021
Walter Roberson
on 20 Feb 2021
Edited: Walter Roberson
on 20 Feb 2021
Should be okay provided that you have more than one hour of data being selected.
x = datetime('2020-05-05 00:00'):hours(1):datetime('2020-05-05 23:00');
y = rand(1,length(x));
plot(x, y)
Anders Vigen
on 20 Feb 2021
Walter Roberson
on 20 Feb 2021
load_demand = readtable("Demand_timeseries_1hourResolution.xlsx");
mask = isbetween(load_demand.Time, datetime('2020-05-05'), datetime('2020-05-06')-minutes(1));
x = load_demand.Time(mask);
y = load_demand{mask,3};
plot(x, y);
Anders Vigen
on 21 Feb 2021
Walter Roberson
on 21 Feb 2021
load_demand = readtable("Demand_timeseries_1hourResolution.xlsx");
mask = isbetween(load_demand{:, 1}, datetime('2020-05-05'), datetime('2020-05-06')-minutes(1));
x = load_demand.Time(mask);
y = load_demand{mask,3};
plot(x, y);
Walter Roberson
on 21 Feb 2021
Edited: Walter Roberson
on 21 Feb 2021
I do not have your file so I was guessing about the variable name based on some of your other comments in other posts.
Anders Vigen
on 21 Feb 2021
Walter Roberson
on 21 Feb 2021
load_demand = readtable("Demand_timeseries_1hourResolution.xlsx");
load_demand.Time = load_demand.Date + hours(load_demand.Hours);
mask = isbetween(load_demand{:, 1}, datetime('2020-05-05'), datetime('2020-05-06')-minutes(1));
x = load_demand.Time(mask);
y = load_demand{mask,3};
plot(x, y);
Walter Roberson
on 21 Feb 2021
This could have been resolved days ago if you have attached a sample file.
Anders Vigen
on 21 Feb 2021
Walter Roberson
on 21 Feb 2021
The representation of hours turned out to be strange :(
load_demand = readtable("Demand_timeseries_1hourResolution.xlsx");
h = cellfun(@(S) sscanf(S, '%d', 1), load_demand.Hours);
load_demand.Time = load_demand.Date + hours(h);
mask = isbetween(load_demand{:, 1}, datetime('2020-05-05'), datetime('2020-05-06')-minutes(1));
x = load_demand.Time(mask);
y = load_demand{mask,3};
plot(x, y);
Anders Vigen
on 23 Feb 2021
Hi, @Anders Vigen
Here I give a Example:
tt = datetime+years(1:10); % 比如从现在时间开始,连续十年时间点
y = rand(10,1);
TT = timetable(tt',y)
plot(TT.Time,y,LineWidth=2)
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