MATLAB Answers

Different rows height in tiled layout

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Pawel Kubik
Pawel Kubik on 29 Mar 2021
Edited: Pawel Kubik on 13 Apr 2021
Hello,
is it possible to adjust row height in tilled layout? I have six plots in tiled layout (2x3). Each of them has own legend. In first and second plot there is 6 items, but in next plots there is only one item to display in legend.
The problem is that all tiles has the same size so there is large space between second and last row. Is it possible to change it?
X = 0:0.01:2*pi;
Y = sin(X);
tiledlayout(3, 2)
nexttile
hold on
plot(X, Y, "DisplayName",'A1')
plot(X, Y, "DisplayName",'A2')
plot(X, Y, "DisplayName",'A3')
plot(X, Y, "DisplayName",'A4')
plot(X, Y, "DisplayName",'A5')
plot(X, Y, "DisplayName",'A6')
legend
nexttile
hold on
plot(X, Y, "DisplayName",'A1')
plot(X, Y, "DisplayName",'A2')
plot(X, Y, "DisplayName",'A3')
plot(X, Y, "DisplayName",'A4')
plot(X, Y, "DisplayName",'A5')
plot(X, Y, "DisplayName",'A6')
legend
nexttile
hold on
plot(X, Y, "DisplayName",'A1')
legend
nexttile
hold on
plot(X, Y, "DisplayName",'A1')
legend
nexttile
hold on
plot(X, Y, "DisplayName",'A1')
plot(X, Y, "DisplayName",'A2')
plot(X, Y, "DisplayName",'A3')
plot(X, Y, "DisplayName",'A4')
legend
nexttile
hold on
plot(X, Y, "DisplayName",'A1')
plot(X, Y, "DisplayName",'A2')
plot(X, Y, "DisplayName",'A3')
plot(X, Y, "DisplayName",'A4')
legend
  6 Comments
Adam Danz
Adam Danz on 31 Mar 2021
> I don't see any solution for the problem in matlab.
I think you gave up too quickly 😉
The problem is that the position of tiledlayout axes is not editable and the tile sizes all change when one of their legends gets too big.
There are way to change the legend size that may help (see my answer). You could also use subplot instead of tiledlayout and that solves the problem direclty since subplot axis positions are editable.

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Accepted Answer

Matt J
Matt J on 2 Apr 2021
Edited: Matt J on 2 Apr 2021
Another solution would be to use nested tiledlayouts, e.g.,
m1=[5,6];
m2=[1,1,1,2];
T=tiledlayout(5,1); %Outer layout
t=tiledlayout(T,1,2); %first inner layout
t.Layout.Tile=1;
t.Layout.TileSpan=[2,1];
for i=1:2
nexttile(t);
plot(rand(5,m1(i)));
legend('Location','southoutside')
end
t=tiledlayout(T,2,2); %second inner layout
t.Layout.Tile=3;
t.Layout.TileSpan=[3,1];
for i=1:4
nexttile(t);
plot(rand(5,m2(i)));
legend('Location','southoutside')
end
  1 Comment
Pawel Kubik
Pawel Kubik on 13 Apr 2021
Thak you Matt! It works perfectly.

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More Answers (1)

Adam Danz
Adam Danz on 31 Mar 2021
Edited: Adam Danz on 31 Mar 2021
Options that either fix the problem or provide an alternative to the example provided.
Based on the image shared, it looks like the legend location is set to SouthOutside.
  1. legend('location','eastoutside') instead of SouthOutside.
  2. legend('location','SouthOutside','Orientation','Horizontal')
  3. legend('location','SouthOutside','NumColumns',3)
  4. Use subplots instead of tiled layout. You can change the position/size of axes created by subplot which directly fixes the problem.
  5. Using a global legend if possible.
All of the above were tested using the example code provided by OP (r2021a) and all of those options fixed the problem.

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