How to calculate "CONTRAST PER PIXEL(CPP)" of an image

To measure the quality of an image i'm using Contrast Per pixel(CPP).
It is defined as the average intensity difference between a pixel and its adjacent pixel.
I'm not used to with this metric. If anybody is well known with this metric, please share it.
Thanks

 Accepted Answer

Something like this perhaps (untested)
kernel = [-1, -1, -1, -1, 8, -1, -1, -1]/8;
diffImage = conv2(double(grayImage), kernel, 'same');
cpp = mean2(diffImage);

3 Comments

Could you please explain the program.
Hello sir,
i'm doing a comparative study among Global Histogram Equalization(GHE),
Contrast Limited Adaptive Histogram Equalization(CLAHE) and Brightness
Preserving Bi-Histogram Equalization(BBHE).
The output i get clearly shows that BBHE is the best among these three.
But i cannot conclude based on visualization.
I'm confuse which metric i should use with proper justification. Could you
please suggest me.
Conv2() is a sliding filter. I made a 3 by 3 window that basically takes the (center - upper left) + (center - top left) + (center - upper right) + (center - left) + (center - right) + (center - lower left) + (center - bottom left) + (center - lower right). That is the sum of all the differences between the center and the 8 surrounding pixels. Then I divide by 8 to get the average difference between a pixel and it's neighbors. The conv2() function just does that operation on every single pixel in the image as it slides that window along pixel-by-pixel and carries out those operations. Then we have an image where each pixel is the average difference between the original pixel at that location and the 8 neighbors. The mean2 simply gets the mean over all the pixels.
You would have to have a metric that models human perception. I'm not aware of any, but you might check here: http://en.wikipedia.org/wiki/Video_quality
Thanks for the explanation and the suggestions sir

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More Answers (1)

Dear sir/Madam, Thank you so much for the above code. It helped me to calculate the contrast per pixel. But my output gives negative values. Is that right and how I can say the best contrast enhanced image from the output?
output I got is -58.3770 original image
-499.6260 contrast enhanced image
Looking for a favourable answer. Thank you

2 Comments

Yes, it is possible to get a negative Laplacian for some pixels. I don't know how you got your numbers. To get a nice contrast adjustment, try imadjust().

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