How to remove and replace single arrow using quiver3/arrow3d

Hi,

I have a 4x4x4 lattice which within it has 16 sites which stores in a cell array a vector at each of these sites, which can point in one of 4 directions.

z1 = (1/sqrt(3))*[1;1;1];
z2 = (1/sqrt(3))*[1;-1;-1];
z3 = (1/sqrt(3))*[-1;-1;1];
z4 = (1/sqrt(3))*[-1;1;-1];

I want to make a plot of these "spins" so I run a for loop which goes through the lattice and draws an arrow using arrow3d based on if conditions i.e

 if isequal(latticec{i,j,k},-z1)==1)

 arrow3d([i+z1(1)/1.5,i-z1(1)/1.5],[j+z1(2)/1.5,j-z1(2)/1.5],...
                        [k+z1(3)/1.5,k-z1(3)/1.5],0.9,0.05,0.1,'Blue');

elseif isequal(latticec{i,j,k},z1)==1)
                      arrow3d([i-z1(1)/1.5,i+z1(1)/1.5],[j-  z1(2)/1.5,j+z1(2)/1.5],...
                      [k-z1(3)/1.5,k+z1(3)/1.5],0.9,0.05,0.1,'Red');

and so on for the other 4 vectors. I do it this way because I want basically the middle of the arrow to be at the x,y,z location of the lattice site.

My program then runs through the lattice and picks out a random x,y,z coordinate of the lattice. I flip the value of the vector in the cell array and I want to now draw the arrow so that it has been flipped. But I don't want to run through the whole loop again because I want to scale my lattice to bigger sizes and this would not be efficient. I was instead thinking is there a way to delete just the arrow at that certain point and replace it with an arrow pointing in the opposite direction.

If you can do it using quiver3 thats o.k. I just prefer arrow3d because the visual image is a lot nicer.

Edit: I have decided to use quiver3 because it's too taxing to use arrow3d.