Solve two simultaneous equations for a set value of y

Hi, I want to solve the following two equations, for a set value.

Equation 1

A=(1/x)*(2/(y+1)*(1+(y-1)/2*x^2))^((y+1)/(2*(y-1)));

Equation 2

P=(((y+1)/2*x^2)/(1+(y-1)/2*(x^2)))^(y/(y-1))*((1)/(((2*y)/(y+1))*x^2-((y-1)/(y+1))))^(1/(y-1));

y=1.4, and is always this value

Such that

A*P=1.2, with y=1.4

Need to determine the value of x, which should be 1.928 approximately

Answer 1

[Walter Roberson]

y = 1.4;
syms x
A = (1/x)*(2/(y+1)*(1+(y-1)/2*x^2))^((y+1)/(2*(y-1)));
P = (((y+1)/2*x^2)/(1+(y-1)/2*(x^2)))^(y/(y-1))*((1)/(((2*y)/(y+1))*x^2-((y-1)/(y+1))))^(1/(y-1));

xsol = solve(A*P == 1.2, x)

xsol = 

vpa(xsol)

ans = 

[Bob Sherland]

Thankyou! That's perfect