Array indices must be positive integers or logical values.

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I uploaded my excel file and matlab code.
I want to portray the value of the elevation (El1). But to do this, what I need to do is, The value of Elevation in cell D5 should be the same value of elevation in cell L2. Then the value of the suceeding elevation should be calculated as, the value of the previous elevation minus the value of the difference of Db1 and Da1.
To further explain, the value of the elevation is 6m. Therefore, the elevation in cell D5 should be 6m as well. But the value of the elevation in cell D6 should be like this:
cell D6 = (cell D5 - 1) - (Db1 - Da1). And it should continue on until the last cell of elevation is computed. But of course, it should portray the negative value. So in cell D13, the elevation should be a negative number. I don't know how to portray the value.

Accepted Answer

Yutaka Yamada
Yutaka Yamada on 24 May 2021
Edited: Yutaka Yamada on 24 May 2021
It seems that Elev1 is the initial elevation.
I think it's better to get the array size first like below. Otherwise the array size of Db1 and El1 becoems different.
N = length(Db1);
El1 = zeros(N,1);
El1(1) = Elev1;
for i = 1:N-1
El1(i+1) = El1(i) - (Db1(i+1) - Da1(i+1));
By running above script, you can get the below El1.

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More Answers (1)

KSSV on 24 May 2021
In MATLAB the indices of array should be strictly positive integers. Zeros and negative numbers are not allowed.
This loop in your code:
for i = 0:100
El1(i) = Elev1(i-1) - (Db1 - Da1);
when i = 0, Elev1(-1) and El1(0) are not valid. Thats why you got error. Change the loop index so that the index is positive.
KSSV on 24 May 2021
Edited: KSSV on 24 May 2021
If you put i = 1:100, Elev1(0) you will get and this will be an error. By the way Elev1 looks to be a constant? Not an array. And also Db1 and Da1 are arrays...the logic is not correct.

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