inverse of tan at 90 degree

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mukesh bisht
mukesh bisht on 25 May 2021
Answered: Star Strider on 25 May 2021
Hi.
Iam using "atand((y2-y1)/(x2-x1))" function to calculate angle. But i incure problem when my denomitor is zero. Sometimes it gives +90 and sometimes -90 degree, even though sign of cordinates of every point is same.
Please suggest way to resolve this issue.
  1 Comment
James Tursa
James Tursa on 25 May 2021
Please give specific example, with numbers, to show where you are getting +90 and -90 even though you think the signs of the inputs are the same.

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Answers (1)

Star Strider
Star Strider on 25 May 2021
A more robust approach would be atan2d, since it provides a 4-quadrant angle.
y2 = 20;
y1 = 10;
x2 = 42;
x1 = 42;
Theta1 = atan2d((y2-y1), (x2-x1))
Theta1 = 90
y2 = 10;
y1 = 20;
x2 = 42;
x1 = 42;
Theta2 = atan2d((y2-y1), (x2-x1))
Theta2 = -90
.

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