MATLAB Answers

harley
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finding closest values in array

Asked by harley
on 6 Aug 2013
Hello, want to locate a value from an pH array when closest to 4.756 and then locate the corresponding Vb value associated with that pH value. Any help would be appreciated. See last 2 lines.
format short
Kw = 1e-14;
Ka = 1.755388e-5;
pKa = 4.756;
%
Ca = 0.5;
Cb = 0.1;
Va = 100;
Vb = 0.05:0.05:2000;
Ma = (Ca * Va) / 1000;
Mb = (Cb .* Vb) ./ 1000;
for i = 1:length(Mb)
M_excess = Ma - Mb(i);
if abs(M_excess)<eps
Hplus = Ka * ((Ma_final * 0.999999) ./ Mb_final);
Vb_ev = Vb(i);
pH_ev = pH(end);
elseif M_excess > 0
Ma_final = (M_excess * 1000) ./ (Va + Vb(i));
Mb_final = (Mb(i) * 1000) ./ (Va + Vb(i));
Hplus = Ka * (Ma_final ./ Mb_final);
elseif M_excess < 0
OH = (M_excess * 1000 * (-1)) ./ (Va + Vb(i));
Hplus = Kw ./ OH;
end
pH(i) = -log10(Hplus);
end
%
pH_Mid_Pt2 = find pH value when closest to 4.756;
Vb_Mid_Pt2 = find corresponding Vb value at pH_Mid_Pt2;

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1 Answer

Answer by Richard Brown on 6 Aug 2013
 Accepted Answer

If I understand correctly, you want to find the pH value in your array closest to 4.756, and pull this value out, together with the corresponding Vb value. If that's right, this should do the trick.
[~, idx] = min(abs(pH - 4.756));
pH_Mid_Pt2 = pH(idx);
Vb_Mid_Pt2 = Vb(idx);

  1 Comment

harley
on 6 Aug 2013
thanks richard, a lot easier than the way i was trying.

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