How to replace a number in a row vector with NaN in certain condition

I have raw vector like this

x = [15 13 9 20 12 15 2 25 17 3 2 5 18 4 12 30 32 40 1 19];

What I need is to replace a number with NaN when the following condition happen.

Whenever the abs difference between x(i) and x(i+1) is >10 replace x(i+1) with NaN , and continue next computation between x(i) and x(i+2) by skipping the value that is assigned as ‘NaN’. If the abs diff between x(i) and x(i+2) is <10, Then the next computation has to be between x(i+2) and x(i+3). But if the abs diff between x(i) and x(i+2) was >10, x(i+2) would be replace by ‘Nan” and next computation would be between x(i) and x(i+3).

In similar way computation continue and returned result should be as follow

x_new = [15 13 9 NaN 12 15 NaN NaN 17 NaN NaN NaN 18 NaN 12 NaN NaN NaN NaN 19]

Answer 1

[per isakson]

abs(x(6)-x(8)) is equal to 10. Accourding to x_new, x(8) should be replaced by NaN. Thus I have use ">=".

%%
vec = [15 13 9 20 12   15 2 25 17 3   2 5 18 4 12   30 32 40 1 19];
len = numel( vec );
new = vec;
pos = 1;
for jj = 2 : len
    if abs(vec(pos)-vec(jj)) >= 10  % Notice ">="
        new(jj) = nan;
    else
        pos = jj;
    end
end
%%
x_new = [15 13 9 NaN 12 15 NaN NaN 17 NaN NaN NaN 18 NaN 12 NaN NaN NaN NaN 19];
disp( x_new ), disp( new ) 

    15    13     9   NaN    12    15   NaN   NaN    17   NaN   NaN   NaN    18   NaN    12   NaN   NaN   NaN   NaN    19

    15    13     9   NaN    12    15   NaN   NaN    17   NaN   NaN   NaN    18   NaN    12   NaN   NaN   NaN   NaN    19

[Yared Daniel]

Thank you so much for understanding my question and solving exactly what I need