how to create an array(1 by 5000) having random values in the range(9-11).

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sanky kumar
sanky kumar on 10 Sep 2013
i have to put the array value as input for sine function, but i guess there are certain limitations for that. it would be great if you could help P.S: new to matlab excuse my immaturity.

Answers (1)

Attila
Attila on 10 Sep 2013
Hi,
Use the uniform distribution function rand(), that outputs values between 0..1 and multiply the values by 2 and add the base 9:
uni = rand(1,5000)*2 + 9
  2 Comments
Attila
Attila on 10 Sep 2013
There are no limitations. As sine is a periodic function, you can input almost any value. It will return a vector with an identical shape as the input.
results = sin(uni)
plot(1:5000, results, 1:5000, uni)
Is this what you needed?
Edit: MATLAB encourages working with matrices instead of loops. Usually there is a workaround to avoid loops and most of the basic functions can accept vector inputs.

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