How do I code to normalize a matrix by dividing each index by the max abs value in the row

A = input('Enter matrix for normalization:'); [x,y] = size(A);

z=abs(C); m=0; n=0;

for i=1:x

end

 disp(n)

Answer 1

[Azzi Abdelmalek]

A=[2 7;8 10]
out=A/max(abs(A(:)))

[Sterlin]

Thanks Azzi. That definitely shortened my code and I learned a new command.

[Jan]

But this does not solve the question: "dividing each index by the max abs value in the row".

Answer 2

[Jan]

A = [2 7;8 10];
m = max(abs(A), [], 2);
B = bsxfun(@rdivide, A, m);